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harkovskaia [24]
3 years ago
6

If 4.59 g of potassium reacts with 3.6 g of sulfur according to the following reaction, how many grams of potassium sulfide can

theoretically be produced? Please identify the limiting and excess reactants: 2K + S -> K^2S
Chemistry
1 answer:
EleoNora [17]3 years ago
8 0
First convert the amount of grams you have of each substance to moles. Find your limiting reactant by calculating how many grams are needed to complete this reaction. If done correctly, you would see that we need .226 moles of Potassium to complete this reaction. However, we only have .118 moles of Potassium, so K must be our limiting reactant. Then use the moles of K to find out how many moles of K^2S are made. Then convert the amount of moles of K^2S to grams and you should get 10.3 g K^2S
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A sample of 5.72 g of liquid 1-propanol, C, H, O, is combustod with 43.4 g of oxygen gas, Carbon dioxide and water are
bekas [8.4K]

Answer:

2C3H8O + 9O2 ==> 6CO2 + 8H2O ... balanced equation

moles propanol = 5.26 g x 1 mol/60.1 g = 0.0875 moles

moles O2 = 31.8 g x 1 mol/31.9 g = 0.997 moles O2

Propanol is limiting based on the mol ratio in balance equation of 2 : 9

To find mass of O2 (excess reagent) left over, we will first find moles O2 used up.

moles O2 used = 0.0875 mol propanol x 9 mol O2/2 mol propanol = 0.394 moles O2 used

moles O2 left over = 0.997 mol - 0.394 mol = 0.603 mol O2 left

mass O2 left = 0.603 mol O2 x 32 g/mol = 19.3 g O2 left over

6 0
2 years ago
I don't know how to do this, pls help!
Aliun [14]
Cations from smallest to largest
Li⁺ ,Na⁺, K⁺ (from Periodic Table, the bigger number of period, the bigger size, of atom, so the bigger size of cation)

1) LiF smaller  cation then KF
1,036                                 <span>853
</span><span>The lattice energy increases as cations get smaller, as shown by LiF and KF.
</span><span>I think this one should be correct answer, because the compared substances have also the same anion, and we can compare cations in them.

2) The same cation Li , so wrong statement.

3)</span>The same cation Na , so wrong statement.

4) NaCl smaller cation then KF
  786                                   853
7 0
3 years ago
Read 2 more answers
Balance the following chemical equation.<br><br> CCl4 -&gt; ___ C+ ___ Cl2
Bingel [31]

Answer:

Explanation:

CCl4 => C + 2Cl2

6 0
2 years ago
What are the names of the following three compounds (see attached)
balu736 [363]

Answer:

1. 4-ethyl-1-heptene

2. 6-ethyl-2-octene

3. 1-butyne

Explanation:

The compounds are named according to IUPAC rules.

Compound 1:

  • Identify the longest carbon chain. This chain is called the parent chain.
  • Identify all of the substituents (groups appending from the parent chain).
  • The parent chain is numbered so that the multiple bonds have the lowest numbers (double has the priority over alkyl substituents).
  • The longest chain contains 7 carbon atoms, so taken the name hept.
  • The double bond between C1 and C2, so take no. 1 and add the suffix ene to hept "1-heptene".
  • The ethyl group is the alkyl substituent on position 4.
  • So the name is 4-ethyl-1-heptene.

Compound 2:

  • Identify the longest carbon chain. This chain is called the parent chain.
  • Identify all of the substituents (groups appending from the parent chain).
  • The parent chain is numbered so that the multiple bonds have the lowest numbers (double has the priority over alkyl substituents).
  • The longest chain contains 8 carbon atoms, so taken the name oct.
  • The double bond between C2 and C3, so take no. 2 and add the suffix ene to oct "2-octene".
  • The ethyl group is the alkyl substituent on position 6.
  • So the name is 6-ethyl-2-octene.

Compound 3:

  • Identify the longest carbon chain. This chain is called the parent chain.
  • Identify all of the substituents (groups appending from the parent chain), there is no substituents.
  • The parent chain is numbered so that the multiple bonds have the lowest numbers (Triple bond here take the lowest number).
  • The longest chain contains 4 carbon atoms, so taken the name but.
  • The triple bond between C1 and C2, so take no. 1 and add the suffix yne to but "1-butyne".
  • So the name is 1-butyne.

7 0
3 years ago
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3 years ago
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