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Aleonysh [2.5K]

2 years ago

13

On a map Rossville and Smithtown are 5 1/2 inches apart. If the actual distance between the town is 16 1/2 miles, to what unit r

ate is the map drawn?
A. 1 inch = 2 1/2 miles
B. 1 inch = 3 miles
C. 1 inch = 3 1/3 miles
D. 1 inch = 11 miles

2 answers:

nikdorinn [45]2 years ago

6 0

The answer is C because it obviously is 1 2 3 4 5 6 7 8 9 10

melisa1 [442]2 years ago

5 0

Answer:

c

Step-by-step explanation:

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lord [1]

Answer:

D.

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What is the sum of n=-2 and m=5

baherus [9]

Answer:

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4 0

2 years ago

How do you solve it?

Elis [28]

At heart we're being asked for a line through two points,

$(40^\circ \textrm{ C}, 355 \textrm { m/s}) \quad \textrm{and} \quad (49^\circ \textrm{ C}, 360 \textrm { m/s})$

In general the line through (a,b) and (c,d) is

$(y-b)(c-a)=(x-a)(d-b)$

Check that you understand why both (a,b) and (c,d) are on this line.

Here our indepedent variable, instead of x, is T, temperature. Our dependent variable is v, velocity. Substituting,

$(v - 355)(49 - 40) = (T - 40)(360 - 355)$

$9(v - 355) = 5(T - 40)$

$v-355 = \frac 5 9 T - \frac{200}{9}$

$v= \frac 5 9 T - \frac{200}{9} + 355$

$v= \frac 5 9 T + \frac{2995}{9}$

That's our answer; let's check it.

When T=40, v = (5/9)40 + (2995/9) = 355 good

When T=49, v= (5/9)49 + (2995/9) = 360 good

7 0

2 years ago