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Aleonysh [2.5K]
2 years ago
13

On a map Rossville and Smithtown are 5 1/2 inches apart. If the actual distance between the town is 16 1/2 miles, to what unit r

ate is the map drawn?
A. 1 inch = 2 1/2 miles
B. 1 inch = 3 miles
C. 1 inch = 3 1/3 miles
D. 1 inch = 11 miles
Mathematics
2 answers:
nikdorinn [45]2 years ago
6 0
The answer is C because it obviously is 1 2 3 4 5 6 7 8 9 10
melisa1 [442]2 years ago
5 0

Answer:

c

Step-by-step explanation:

You might be interested in
If f(x) = 2x + 3 and g(x) = x^2 + 1,find f(g(3)).<br> A.) 23<br> B.) 47<br> C.) 82<br> D.) 90
marta [7]
The answer is A). 23. 
<span>g(x)= 2x + 3 </span>
<span>g(x) = x^2 + 1 </span>
<span>g(3) = 10 </span>
<span>f(g(3)) </span>
<span>= f(10) </span>
<span>= 23 </span>
6 0
3 years ago
It was recently estimated that females outnumber males by about three or two. If there are 1770 people in a county, how many of
max2010maxim [7]

GIVEN

1) Females outnumber males by 3 to 2.

2) There are 1770 people in the city.

SOLUTION

Let the number of males be x and the number of females y. Therefore, the total number of people can be written to be:

x+y=1770\text{   -----------(1)}

If there are 3 females for every 2 males, we have that:

\begin{gathered} \frac{y}{3}=\frac{x}{2} \\ \therefore \\ x=\frac{2y}{3}\text{   ----------(2)} \end{gathered}

We can substitute equation (2) into equation (1) and solve for y:

\begin{gathered} \frac{2}{3}y+y=1770 \\ \frac{2y+3y}{3}=1770 \\ 5y=1770\times3 \\ 5y=5310 \end{gathered}

Dividing both sides by 5, we have

y=1062

There are 1062 females in the county.

3 0
1 year ago
Help answering this simple Series Question? I don't know what I did wrong!
Tatiana [17]
Looks like you just evaluated the summand for the given value of n, whereas the question is asking you to find the value of the sum for the first n terms.

Let S_k=\displaystyle\sum_{n=1}^k\frac3{(-2)^n}. Then S_k is the kth partial sum.

S_1 happens to be the first term in the series, which is why that box is marked correct:

S_1=\displaystyle\sum_{n=1}^1\frac3{(-2)^n}=\frac3{(-2)^1}=-1.5

But the next partial sum is not correct:

S_2=\displaystyle\sum_{n=1}^2\frac3{(-2)^n}=\frac3{(-2)^1}+\frac3{(-2)^2}=-0.75

and this is not the same notion as the second term (which indeed is 0.75) in the series.
5 0
3 years ago
A line with a slope of 2/5 passed through the point (-2,3). Write the equations of the line in point-slope form and graph the li
DochEvi [55]

Answer:

y - 3 = (2/5)(x + 2)

Step-by-step explanation:

Start with the general point-slope form of the equation of a straight line:

y - k = m(x - h).  Now substitute -2 for h and 3 for k, and also 2/5 for m:

y - 3 = (2/5)(x + 2)

5 0
3 years ago
Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

  • There are 100 students
  • 65 are members of a mathematics club
  • 40 are members of a physics club
  • 10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

  club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

Learn more:

You can learn more about word problems in brainly.com/question/8907574

#LearnwithBrainly

5 0
3 years ago
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