The event will have 27 tables, with 2 adults and 3 children in each table.
Step-by-step explanation:
The greatest number of tables the planner can set up is determined by finding the greatest common factor in 54 and 81. This is given by;
54 81----------------divided by 3
3 18 27---------------divided by 3
3 6 9---------------divided by 3
3 2 3---------------no common divisor
The greatest number of table will be given by : 3×3×3=27
The number of adults in each table will be 2
The number of children in each table will be 3
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Greatest common factor : brainly.com/question/13133626
Keyword : greatest number
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Urban ecosystem. 1) Birds - their limiting factor is the number of trees that can support their young2) Trees - amount of fertile soil, since buildings are abundant they can't grow properly3) Wild dogs - having a hard time to feed themselves due to scarce foodThank you for your question. Please don't hesitate to ask in Brainly your queries.
<span>There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.
So, total number of chairs in 4 long rows= 4x
Total number of chairs in 5 short rows = 5y
Total number of chairs in the theater on a normal day = 4x + 5y
When 2 chairs are added to each long row, the number of chairs will change to (x+2).
So, total number of chairs in 4 long rows will be = 4(x+2)
When 3 chairs are added to each short row, the number of chairs will change to (y+3)
So, total number of chairs in 5 short rows will be = 5(y+3)
Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)
= 4x + 8 + 5y + 15
= 4x + 5y + 23
Thus we can say the number of chairs increase by 23 as compared to a normal day.
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Factor the numerator and denominator and cancel the common factors.
4x^4 - 2
