I don’t know The answer but I tried
We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
Answer:
Amount of gas that can be hold by Joe's tank = 16 gallons.
Step-by-step explanation:
Given that Joe's gas tank is 1/4 full. After he buys 6 gallons of gas, it is 5/8 full. Now we need to find about how many gallons can Joe's tank hold.
So let's find change that happened after filling the gas.
Change = (5/8 full) - (1/4 full)
Change = (5/8 - 1/4) full
Change = (5/8 - 2/8) full
Change = (5 - 2)/8 full
Change = 3/8 full
So that means 3/8 full happens in 6 gallons
then 1 full will happen in 6/(3/8) gallons = 6*(8/3) gallons = 48/3 gallons = 16 gallons
So the amount of gas that can be hold by Joe's tank = 16 gallons.
Answer:
that answer was wrong your dum
Step-by-step explanation:
7x (2x^2 - 3) is your answer my dude/lady
