In this question, one parent is homozygous recessive (bbee) and other parent is dihybrid (BbEe)
B - black fur dominant trait
b - white fur recessive
E- black eyes dominant
e - red eyes recessive
a punnett square shows all the possible combinations of genotypes with the corresponding phenotypes that the offspring could inherit.
the genotypes and their phenotypes for the offspring are given below ;
BBEE / BbEe / BbEE / BBEe - black fur and black eyes
Bbee / BBee - black fur and red eyes
bbee - white fur and red eyes
bbEe / bbEE - white fur and black eyes
after analysing the punnett square the following results are obtained;
black fur and black eyes - BbEe- 4/16
black fur and red eyes -Bbee - 4/16
white fur and black eyes - bbEe - 4/16
white fur and red eyes -bbee - 4/16
A 'red' apple does not emit red light. Rather, it simply absorbs all the frequencies of visible light shining on it EXCEPT for a group of frequencies that is perceived as red, which are REFLECTED. An apple looks red to us because it REFLECTS infrared waves.
Loss of Rb, an important part of the G1-S transition checkpoint, can result in uncontrolled cell cycle progression and cancer. All of the following would mimic loss of Rb except constitutively active Ras GTPase activating protein. Correct answer: letter E.
Constitutively active Ras GTPase activating protein would not mimic loss of Rb, because it would not directly result in uncontrolled cell cycle progression.
<h3>What is Retinoblastoma (RB)?</h3>
Rb is an important tumor suppressor protein that works to inhibit cell cycle progression by preventing the activation of E2F transcription factors. Constitutively active Ras GTPase activating protein would not directly interfere with the Rb-E2F pathway, which is necessary for uncontrolled cell cycle progression and cancer.
Learn more about the cell cycle:
brainly.com/question/2457509
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Answer:
All cells except sex cells
Explanation:
As fas as i remember 20% of whole cell is RBC
so the answer is 2×10^13 !!