Answer:
3p^3 + qp^2 - pq^2 + 3q^3
Step-by-step explanation:
(p²-pq + q²) ( 3p+ 3q)
3p^3 + 3qp^2 - 3qp^2 - 3pq^2 + 3pq^2 + 3q^3
3p^3 + qp^2 - pq^2 + 3q^3
You need to a table of the standard normal cumulative distribution
Here is one:
https://math.ucalgary.ca/files/math/normal_cdf.pdf
the closest value I see is 0.85
Answer:
25.12 meters
Step-by-step explanation:
The circumference of a circle is given by
(1)
where:
r is the radius of the circle
In this problem, the parachute has a diameter of 8 meters:
d = 8 m
The radius of a circle is equal to half of its diameter, so the radius of the parachute is:
And therefore, by applying eq.(1) we can find the circumference of the circle:
Area = PI * radius^2
Circumference = 2 * PI * radius
radius = Circumference / 2 * PI
So, Area = PI * (Circumference / 2 *PI) * (Circumference / 2 *PI)
So, Area = Circumference^2 / (4*PI)
The question is worded incorrectly. It should say the DENSITY of water is 62 1/2 lbs per cubic foot. Divide the weight by the density to get volume.
(150 lbs) / (62.5 lbs/ft3) = ? ft3 (the two 3's are exponents. so it'd be ft then an exponent of 3.)
