Answer:
Marcela can take up to 13 units.
Step-by-step explanation:
In order to find the number of units that Marcela can take for her college classes, we can set up an inequality and solve for the variable. Since each unit costs $105, we can say that 105u ≤ 1365 where u = the number of units. The number of units multiplied by the cost per unit, must be less than or equal to $1,365. In order to solve for 'u', we can use inverse (opposite) operations and get rid of the coefficient by dividing both sides of the inequality by 105. 1365÷105 = 13. So, the number of units that Marcela can take must be less than or equal to 13 units.
Answer:
Step-by-step explanation:
You're given a coordinate in the form of (x, y) and you're also given the vertex in the form of (h, k). We will use those in the vertex form of the equation
and solve for a. Filling in:
which simplifies a bit to
and a bit more to
. Add 3 to both sides to get
-8 = 4a so
a = -2
The equation, then, is
Answer: See below
Step-by-step explanation:
Simplify:
Answer:
ekena la pernina de la abobo Kot Sa Rita kolos talas 8
Deacon Middle School
5x = number of boys
4x = number of girls
where x is some unknown number for now
(number of boys)+(number of girls) = 270 students total
5x+4x = 270
9x = 270
x = 270/9
x = 30
Since x = 30, this means
number of girls = 4x
number of girls = 4*30
number of girls = 120
There are 120 girls at Deacon Middle School
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Similarly, for Meadow Middle school
number of boys = 4y
number of girls = 5y
for some number y
(number of boys) + (number of girls) = 180 students total
4y+5y = 180
9y = 180
y = 180/9
y = 20
making,
number of girls = 5*y
number of girls = 5*20
number of girls = 100
so there are 100 girls at Meadow Middle School
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In summary so far, there are...
120 girls at Deacon Middle School
100 girls at Meadow Middle School
In total 120+100 = 220 girls from both schools
This is out of 270+180 = 450 students total
Divide the two values (220 and 450) to get
220/450 = 22/45
The final answer is 22/45
It cannot be reduced further as there are no common factors (other than 1) between 22 and 45
