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enot [183]
3 years ago
5

F(x) =x2-17x+60 how to find the zeros of the function​

Mathematics
2 answers:
levacccp [35]3 years ago
7 0

Answer:

x = 5, x = 12.

Step-by-step explanation:

This is a quadratic function which may factor to the form (x - a)(x - b) whose zeroes are a and b.

To factor this we need two numbers whose product is +60 and whose sum is -17. They are -5 and -12 ( -5*-12 = 60 and -12 + -5 = -17).

So the factors are :

(x - 5)(x - 17)

To find the zeros we equate this to 0:

(x - 5)(x - 17) = 0

x- 5 = 0 gives x = 5

and

x - 12 = 0 gives x = 12.

sergiy2304 [10]3 years ago
3 0

Answer:

x = 1&16

Step-by-step explanation:

f(x) = 0 then

0 =x^2 - 17x + 16

(x-1)(x-16) =0

x -1 =0 or x-16=0

x =1 & x = 16

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a) $340

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Step-by-step explanation:

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b) in July he earned 160 ÷ 8 = $ 20

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2 years ago
1. What is the constant rate of change between x and y in the table below?
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a

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2 years ago
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Describe the steps in solving the linear equation 3(3x − 8) = 4x + 6.
Fittoniya [83]

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x=6

Step-by-step explanation:

3(3x-8)=4x+6

First you would distribute the 3 on the L side to the parenthasies

9x-24=4x+6

Then, you would subtract 4x from both sides because it is the smallest X value

5x-24=6

Add 24 to both sides (inverse operations)

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5 0
3 years ago
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Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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