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Musya8 [376]
3 years ago
7

What is an equation of the line that passes through the points (-3,3) and (-6,2)?

Mathematics
2 answers:
Katena32 [7]3 years ago
7 0
Answer:

Y=1/3x+4

Explanation: point intercept formula
qwelly [4]3 years ago
4 0

Answer:

y=1/3x+4

Step-by-step explanation:

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What is g(x) I need your help
velikii [3]

Answer:

D ,  i thinks this is the answer  because i cant see the g(x) good

Step-by-step explanation:

5 0
3 years ago
Heights​ (cm) and weights​ (kg) are measured for 100 randomly selected adult​ males, and range from heights of 133 to 193 cm and
yawa3891 [41]

Answer:

The weight of an adult male who is 172 cm tall is 89.36 kg.

Step-by-step explanation:

The regression equation representing the relationship between height and weight of a person is:

\hat y=-105+1.13x

Here

<em>y</em> = weight of a person

<em>x</em> = height of a person

The information provided is:

\bar x=167.90\ cm\\\bar y=81.47\ kg\\r (X, Y) = 0.228\\p-value=0.023\\\alpha =0.05

The hypothesis to test the significance of the correlation between height and weight is:

<em>H₀</em>: There is no relationship between the height and weight, i.e. <em>ρ</em> = 0.

<em>Hₐ</em>: There is a relationship between the height and weight, i.e. <em>ρ </em>≠ 0.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level, then the null hypothesis will be rejected and vice-versa.

According to information provided:

<em>p</em>-value = 0.023 < <em>α</em> = 0.05

The null hypothesis was rejected at 5% level of significance.

Thus, concluding that there is a relationship between the height and weight.

Compute the weight of an adult male with height, <em>x</em> = 172 cm as follows:

\hat y=-105+1.13x

  =-105+(1.13\times 172)\\=-105+194.36\\=89.36

Thus, the weight of an adult male who is 172 cm tall is 89.36 kg.

5 0
3 years ago
Match the terms to their correct definitions.
Inessa [10]
Not 100% positive, but I think that it’s
13
10
9
16
15
11
14
12
I hope this helps
5 0
2 years ago
One urn contains one blue ball (labeled b1) and three red balls (labeled r1, r2, and r3). a second urn contains two red balls (r
Flura [38]

Answer:

12 possibilities

Step-by-step explanation:

In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.

The same thing occurs in the second urn, as all balls have different labels.

The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).

For the first urn, we have a combination of 4 choose 2:

C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities

For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.

In total we have 6 + 6 = 12 possibilities.

3 0
3 years ago
Read 2 more answers
What shape is this??
wariber [46]
The shape shown here is a pentagonal pyramid, because it has a pentagonal base and a pointy tip.
6 0
3 years ago
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