Question

The heat of vaporization of diethyl ether is . Calculate the change in entropy when of diethyl ether boils at . Be sure your answer contains a unit symbol. Round your answer to significant digits.

Answer 1

Answer:

$\Delta S=900\frac{J}{K}$

Explanation:

Hello!

In this case, since the information is not missing, the following one will be used as it is found on similar problems:

$\Delta h=26.7kJ/mol\\T_b=34.6\°C\\m=769.0g$

In such a way, we use the following equation to compute the entropy:

$\Delta S=\frac{n\Delta h}{T_b}$

Whereas n (moles) are computed by using its molar mass (74.14 g/mol) as follows:

$n=769.0g*\frac{1mol}{74.14g}=10.4mol$

$\Delta S=\frac{10.4mol*26.7\frac{kJ}{ml} }{(34.6+273.15)K}\\\\\Delta S=0.900 \frac{kJ}{K} \\\\\Delta S=900\frac{J}{K}$

Best regards!