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cupoosta [38]
4 years ago
15

Consider the following reversible reaction. Upper C upper O (g) plus 2 upper H subscript 2 (g) double-headed arrow upper C upper

H subscript 3 upper O upper H (g). What is the equilibrium constant expression for the given system?
Chemistry
1 answer:
Rina8888 [55]4 years ago
3 0

Answer:

Answer:K subscript e q equals StartFraction StartBracket upper C upper O subscript 2 EndBracket StartBracket upper C a upper O EndBracket over StartBracket upper C a upper C upper O subscript 3 EndBracket EndFraction

Explanation: the answer has it's root in Law of mass action which states that; the rate of a chemical reaction is directly proportional to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients.

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The mass number refers to the totaol number of _____and_____which can be found int he nucleus of the atom
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The mass number refers to the total number of protons and neutrons which can be found in the nucleus of the atom.
8 0
3 years ago
In h2o, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a
Murrr4er [49]
The hydrogen and oxygen<span> atoms from H</span>₂O are <span>bonded together through covalent </span>bonding. 
3 0
3 years ago
The term biodiversity means the variety of organism (true or false)
NARA [144]

Answer:

true

Explanation:

6 0
3 years ago
An object has a mass of 0.0124kg and a volume of 1893mm3. What is its density in grams per cubic centimeter?
anyanavicka [17]

Answer:

6.25×10⁻⁶ g / cm³

Explanation:

Density is the relation between mass and volume as this formula shows.

Density of a compound = Mass of the compound / Volume of compound

In the values, we were given:

0.0124 kg / 1983 mm³ = 6.25×10⁻⁶ kg/mm³

This number means that in a volume of 1 mm³ of compound, the mass of it occupies 6.25×10⁻⁶ kg. Let's make a rule of three:

1 cm³ = 1×10⁻³ mm³

In 1 mm³ we have 6.25×10⁻⁶ kg of compound

So in 1×10⁻³ mm³ we would have (1×10⁻³ mm³ . 6.25×10⁻⁶ kg) / 1 mm³ =

6.25×10⁻⁹ kg

Now let's convert the kg to g.

1 kg  = 1000 g

6.25×10⁻⁹ kg . 1000 = 6.25×10⁻⁶ g

Finally density is : 6.25×10⁻⁶ g / cm³

5 0
3 years ago
Which distinguishes an atom of one element from an atoms of a different element?
dalvyx [7]

Answer:

The number of protons you welcome

Explanation:

7 0
3 years ago
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