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cupoosta [38]
4 years ago
15

Consider the following reversible reaction. Upper C upper O (g) plus 2 upper H subscript 2 (g) double-headed arrow upper C upper

H subscript 3 upper O upper H (g). What is the equilibrium constant expression for the given system?
Chemistry
1 answer:
Rina8888 [55]4 years ago
3 0

Answer:

Answer:K subscript e q equals StartFraction StartBracket upper C upper O subscript 2 EndBracket StartBracket upper C a upper O EndBracket over StartBracket upper C a upper C upper O subscript 3 EndBracket EndFraction

Explanation: the answer has it's root in Law of mass action which states that; the rate of a chemical reaction is directly proportional to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients.

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Answer: The given statement is TRUE.

Explanation:

An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.

Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.

For example for the given equilibrium reaction;

2H_2O(g)\leftrightharpoons 2H_2(g)+O_2(g)

K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

Thus the given statement that in calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the factors in the equilibrium expression is True.

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hope it helps

Plz mark me as brainleist if helps

Have a great day ahead

3 0
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