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cupoosta [38]
3 years ago
15

Consider the following reversible reaction. Upper C upper O (g) plus 2 upper H subscript 2 (g) double-headed arrow upper C upper

H subscript 3 upper O upper H (g). What is the equilibrium constant expression for the given system?
Chemistry
1 answer:
Rina8888 [55]3 years ago
3 0

Answer:

Answer:K subscript e q equals StartFraction StartBracket upper C upper O subscript 2 EndBracket StartBracket upper C a upper O EndBracket over StartBracket upper C a upper C upper O subscript 3 EndBracket EndFraction

Explanation: the answer has it's root in Law of mass action which states that; the rate of a chemical reaction is directly proportional to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients.

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The point at where the water is changing phase
e-lub [12.9K]

Answer:

the point at there the water is changing is titled "getting dressed"

6 0
3 years ago
Calculate the mole fraction of cai2 in an aqueous solution prepared by dissolving 0.400 moles of cai2 in 850.0 g of water.
alukav5142 [94]
1) Formulas:

a) mole fraction of component 1, X1

X1 =  number of moles of compoent 1 / total number of moles

b) Molar mass = number grams / number of moles => number of moles =  number of grams / molar mass


2) Application

Number of moles of CaI2 = 0.400

Molar mass of water = 18.0 g/mol

Number of moles of water: 850.0 g / 18.0 g/mol = 47.22 mol

Total number of moles = 0.400 + 47.22 =47.62

Molar fraction of CaI2 = 0.400 / 47.62 = 0.00840
7 0
3 years ago
Consider the electrolysis of molten barium chloride (bacl2). write the half-reactions. include the states of each species.
aksik [14]
Molten barium chloride is separeted into two species :
BaCl₂(l) → Ba(l) + Cl₂(g),
but first ionic bonds in this salt are separeted because of heat:
BaCl₂(l) → Ba²⁺(l) + 2Cl⁻(l).

Reaction of reduction at cathode(-): Ba²⁺(l) + 2e⁻ → Ba(l).

Reaction of oxidation at anode(+): 2Cl⁻(l) → Cl₂(g) + 2e⁻.

<span>The anode is positive and the cathode is negative.</span>

7 0
3 years ago
I NEED HELP PLEASE, THANKS!
ira [324]

Answer:

About 0.652

Explanation:

Because the reaction is balanced, we can go straight to the next step. The molar mass of potassium is about 39.098, while the molar mass of hydrogen gas is 2 and the molar mass of water is 18. Therefore, 25.5g of potassium would be about 0.652 moles, and 220 grams of water would be about 12.222 moles, making potassium the limiting reactant. Since there is a single unit of each compound on both sides of the equation, there would be an equal amount of moles of potassium and hydrogen, and therefore about 0.652 moles of hydrogen gas would be produced. Hope this helps!

6 0
3 years ago
Write isotopic symbols in the form AZX for each isotope. a. the copper isotope with 34 neutrons b. the copper isotope with 36 ne
krek1111 [17]

Explanation:

The form AZX denoted that;

Z = The atomic number or proton number (symbol Z) of a chemical element is the number of protons found in the nucleus of every atom of that element.

A = Mass Number ( Sum of Neutrons and Protons)

X represents the element.

A. the copper isotope with 34 neutrons

X = Cu

Atomic Number of Copper, Z = 29

Mass Number, A = 29 + 34 = 63

63.29.Cu

B. the copper isotope with 36 neutrons

X = Cu

Atomic Number of Copper, Z = 29

Mass Number, A = 29 + 36 = 65

65.29.Cu

C. the potassium isotope with 21 neutrons

X = K

Atomic Number of Potassium, Z = 19

Mass Number, A = 19 + 21 = 40

40.19.K

D. the argon isotope with 22 neutrons

X = Ar

Atomic Number of Argon, Z = 18

Mass Number, A = 18 + 22 = 40

40.18.Ar

5 0
3 years ago
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