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melomori [17]
3 years ago
10

There are 33 times as many boys as girls in a room. If 4 boys and 4 girls leave the room, then there will be 5 times as many boy

s as girls in the room. In total, how many boys and girls were in the room originally
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Answer:

here are 3 times as many boys as girls in a room. If 4 boys and four girls leave the room, then there will be 5 times as many boys as girls in the room. In total, how many boys and girls were in the room originally?

8 girls

24 boys

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Select each answer that is true
levacccp [35]

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rational

Step-by-step explanation:

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What are the coordinates of (-3,4) when it is reflected over the y-axis.
AysviL [449]

Answer:

D. (4,3)

Step-by-step explanation:

(-3,4)

Reflection in the y-axis:

Same y, -ve x

(3,4)

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(x,y) goes to (y,x)

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3 0
3 years ago
What is 874 base 9 multiplied by 676 base 9?​
Gekata [30.6K]

Consider the digit expansion of one of the numbers, say,

676₉ = 600₉ + 70₉ + 6₉

then distribute 874₉ over this sum.

874₉ • 6₉ = (8•6)(7•6)(4•6)₉ = (48)(42)(24)₉

• 48 = 45 + 3 = 5•9¹ + 3•9⁰ = 53₉

• 42 = 36 + 6 = 4•9¹ + 6•9⁰ = 46₉

• 24 = 18 + 6 = 2•9¹ + 6•9⁰ = 26₉

874₉ • 6₉ = 5(3 + 4)(6 + 2)6₉ = 5786₉

874₉ • 70₉ = (8•7)(7•7)(4•7)0₉ = (56)(49)(28)0₉

• 56 = 54 + 2 = 6•9¹ + 2•9⁰ = 62₉

• 49 = 45 + 4 = 5•9¹ + 4•9⁰ = 54₉

• 28 = 27 + 1 = 3•9¹ + 1•9⁰ = 31₉

874₉ • 70₉ = 6(2 + 5)(4 + 3)10₉ = 67710₉

874₉ • 600₉ = (874•6)00₉ = 578600₉

Then

874₉ • 676₉ = 578600₉ + 67710₉ + 5786₉

= 5(7 + 6)(8 + 7 + 5)(6 + 7 + 7)(0 + 1 + 8)(0 + 0 + 6)₉

= 5(13)(20)(20)(1•9)6₉

= 5(13)(20)(20 + 1)06₉

= 5(13)(20)(2•9 + 3)06₉

= 5(13)(20 + 2)306₉

= 5(13)(2•9 + 4)306₉

= 5(13 + 2)4306₉

= 5(1•9 + 6)4306₉

= (5 + 1)64306₉

= 664306₉

4 0
3 years ago
28 in 21 in., 20 in.<br> Is this a right triangle?
ankoles [38]

Answer:

No, it is not a right triangle.

Step-by-step explanation:

The simplest way to determine is testing out the numbers with Pythagorian theorem.

If it complies with the theorem, it is a right triangle.

let's assume c = 28, b = 21, and a = 20

the longest side is the hypotenuse so side c (28 in) will be the hypotenuse.

According to the Pythagorian theorem, the square of the length of hypotenuse must equal to the sum of squares of other two sides.

check:

c^2 = 28^2 = 784

a^2 + b^2 = 21^2 + 20^2 = 841

because c^2 is not equal to a^2 + b^2, the triangle is not a right triangle.

7 0
3 years ago
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