Since you technically didn't ask for anything to be solved for, this problem is now solved. Since these types of problems are normally solving for legnth if width is given and vice versa, I will solve for legnth.
perimiter=legnth+legnth+width+width or
p=l+l+w+w
p=2l+2w
subsitute w=6.5 and p=34
34=2l+2(6.5)
34=2l+13
subtract 13 from both sides
21=2l
divide by 2
10.5=l
legnth=10.5 units
Answer:

And
and if we use the following function on the Ti84 plus we got:
invNorm(0.02,0,1)
invNorm(1-0.02,0,1)
And the values with the middle 96% of the values are:

Step-by-step explanation:
For this case we want to find the limits with the middle 96% of the area below the normal curve, then the significance level would be:

And
and if we use the following function on the Ti84 plus we got:
invNorm(0.02,0,1)
invNorm(1-0.02,0,1)
And the values with the middle 96% of the values are:

A dilation by a scale factor of 5 centered at the origin simply multplies by 5 the coordinates of every point. So, the new coordinates are (-5, -25)
Answer:
a. 55.56%
b. 44.44%
c. 3.33%
d. 33.33%
Step-by-step explanation:
total supply = 180
a. In the first factory the total number obtained = 100
probability that the chosen part is from the first
= 100/180
= 0.5556
= 55.56%
b. In the second factory total = 80
probability that the chosen part is from the second
= 80/180
= 0.4444
= 44.44%
c. probability that part chosen at random from 180 is defective
= 2% * 0.5556 + 5% * 0.4444
= 0.02*0.5556 + 0.05*0.4444
= 0.011112 + 0.0222
= 0.03331
= 3.33%
d. probability it came rom the first factory if it is defective

= 
= 
= 0.33357
= 33.33%
Answer: A <em>plane </em>
This needs to be 20 characters long so this is ok