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melomori [17]
2 years ago
10

There are 33 times as many boys as girls in a room. If 4 boys and 4 girls leave the room, then there will be 5 times as many boy

s as girls in the room. In total, how many boys and girls were in the room originally
Mathematics
1 answer:
KATRIN_1 [288]2 years ago
7 0

Answer:

here are 3 times as many boys as girls in a room. If 4 boys and four girls leave the room, then there will be 5 times as many boys as girls in the room. In total, how many boys and girls were in the room originally?

8 girls

24 boys

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I WANT SOLUTION AND EXPLANATION ANSWER IS GIVEN AT LAST!!!
kozerog [31]
<h3><u>Question</u><u>:</u></h3>

<u>The difference between a 2-digit number and the number formed by reversing its digits is 45. If the sum of the digits of the original number is 13, then find the number. </u>

<h3><u>Statement</u><u>:</u></h3>

<u>The difference between a 2-digit number and the number formed by reversing its digits is 45. </u><u>T</u><u>he sum of the digits of the original number is 13</u><u>.</u>

<h3><u>Solution:</u></h3>
  • Let one of the digit of the original number be x.
  • So, the other digit = (13-x)
  • Therefore, the two digit number = 10(13-x) + x = 130-10x+x = 130-9x
  • The number obtained after interchanging the digits is 10x+(13-x) =9x+13
  • Therefore, by the problem

130-9x-(9x+13) = 45

or, 130-9x- 9x-13 = 45

or, -18x = 45-130+13

or, -18x= -72

or, x = 72/18 = 4

or, x = 4

  • So, the original number = 130-9x = 130 -9(4) = 130 - 36 = 94
<h3>Answer:</h3>

The number is 94.

I think the answer you have given isn't right. The answer should be 94.

7 0
2 years ago
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