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melomori [17]
3 years ago
10

There are 33 times as many boys as girls in a room. If 4 boys and 4 girls leave the room, then there will be 5 times as many boy

s as girls in the room. In total, how many boys and girls were in the room originally
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Answer:

here are 3 times as many boys as girls in a room. If 4 boys and four girls leave the room, then there will be 5 times as many boys as girls in the room. In total, how many boys and girls were in the room originally?

8 girls

24 boys

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The perimeter of a rectangle is 34 units and its width is 6.5 units
IgorC [24]
Since you technically didn't ask for anything to be solved for, this problem is now solved. Since these types of problems are normally solving for legnth if width is given and vice versa, I will solve for legnth.

perimiter=legnth+legnth+width+width or
p=l+l+w+w
p=2l+2w
subsitute w=6.5 and p=34
34=2l+2(6.5)
34=2l+13
subtract 13 from both sides
21=2l
divide by 2
10.5=l

legnth=10.5 units

5 0
3 years ago
Find the -scores that bound the middle 96 of the area under the standard normal curve by using the TI-84 calculator.
Korvikt [17]

Answer:

\alpha=1-0.96 =0.04

And \alpha/2= 0.02 and if we use the following function on the Ti84 plus we got:

invNorm(0.02,0,1)

invNorm(1-0.02,0,1)

And the values with the middle 96% of the values are:

z_{\alpha/2}= \pm 2.054

Step-by-step explanation:

For this case we want to find the limits with the middle 96% of the area below the normal curve, then the significance level would be:

\alpha=1-0.96 =0.04

And \alpha/2= 0.02 and if we use the following function on the Ti84 plus we got:

invNorm(0.02,0,1)

invNorm(1-0.02,0,1)

And the values with the middle 96% of the values are:

z_{\alpha/2}= \pm 2.054

6 0
3 years ago
What is the image of (-1,-5) after a dilation by a scale factor of 5 centered at the<br> origin?
Travka [436]

A dilation by a scale factor of 5 centered at the  origin simply multplies by 5 the coordinates of every point. So, the new coordinates are (-5, -25)

4 0
3 years ago
Two different factories both produce a certain automobile part. The probability that a component from the first factory is defec
Ulleksa [173]

Answer:

a. 55.56%

b. 44.44%

c. 3.33%

d. 33.33%

Step-by-step explanation:

total supply =  180

a. In the first factory the total number obtained = 100

probability that the chosen part is from the first

= 100/180

= 0.5556

= 55.56%

b. In the second factory total = 80

probability that the chosen part is from the second

= 80/180

= 0.4444

= 44.44%

c. probability that part chosen at random from 180 is defective

= 2% * 0.5556 + 5% * 0.4444

= 0.02*0.5556 + 0.05*0.4444

=  0.011112 + 0.0222

= 0.03331

= 3.33%

d. probability it came rom the first factory if it is defective

\frac{0.02*0.5556}{0.02*0.5556+0.05*0.4444}

= \frac{0.011112}{0.011112+0.0222}

= \frac{0.011112}{0.033312}

= 0.33357

= 33.33%

5 0
3 years ago
Which is a flat surface with no thickness that contains many lines and extends without end in the directions of all its lines?
Lina20 [59]

Answer: A <em>plane </em>

This needs to be 20 characters long so this is ok

3 0
3 years ago
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