Step-by-step explanation:
–6(x + 5) + 3 = –2(x + 4) – 4x
–6x – 30 + 3 = –2x –8 – 4x
–6x –27 = –6x –8
–6x + 6x = –8 + 27
0 = 19
no solution
-3 × -5 = -15
-15 × 0 = 0
Answer:
The probability is 0.5438
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 0.8599, \sigma = 0.0519](https://tex.z-dn.net/?f=%5Cmu%20%3D%200.8599%2C%20%5Csigma%20%3D%200.0519)
a. If 1 candy is randomly selected, find the probability that it weighs more than 0.8542g.
This is 1 subtracted by the pvalue of Z when X = 0.8542. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{0.8542 - 0.8599}{0.0519}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B0.8542%20-%200.8599%7D%7B0.0519%7D)
![Z = -0.11](https://tex.z-dn.net/?f=Z%20%3D%20-0.11)
has a pvalue of 0.4562
1 - 0.4562 = 0.5438
The probability is 0.5438
If x=0.62y (x=dollar, y=sterling), then you can multiply both sides by 350 to get 350x=0.62*350y=217 sterlings
Answer:
![6^{6}](https://tex.z-dn.net/?f=6%5E%7B6%7D)
Step-by-step explanation:
Step 1: Review exponent laws
Remember that when we divide exponents with the same base we can just subtract the exponents and leave the base the same
Step 2: Solve
÷ ![6^{3}](https://tex.z-dn.net/?f=6%5E%7B3%7D)
![6^{9-3} \\6^{6}](https://tex.z-dn.net/?f=6%5E%7B9-3%7D%20%5C%5C6%5E%7B6%7D)
Step 3: Therefore Statement
Therefore
÷
simplified is ![6^{6}\\](https://tex.z-dn.net/?f=6%5E%7B6%7D%5C%5C)