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vekshin1
2 years ago
8

*PLS HELP*The Question Is In The Attachment​

Mathematics
1 answer:
malfutka [58]2 years ago
5 0

Answer:

Step-by-step explanation:

Rhombus:

Base = b = 14 in

altitude = h = 12 in

Area of rhombus = b*h = 14 * 12 = 168 in²

Triangle:

base = b = 12 in

Height = h = 14 in

Area \ of \ triangle = \dfrac{1}{2}bh=\dfrac{1}{2}*12*14=12*7=84 \ in^{2}

Area of the figure = area of the rhombus + area of the triangle

                               = 168 + 84

                               = 252 in²

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The graph of g(x) is a reflection and translation of ∛x see attachment, please help
svetoff [14.1K]
<h2>Hello!</h2>

The answer is: g(x)=-\sqrt[3]{x-1}

<h2>Why?</h2>

Let's check the roots and the shown point in the graphic (2,-1)

First,

0=-\sqrt[3]{x-1}\\\\0^{3}=(-\sqrt[3]{x-1})^{3}\\\\0=-(x-1)\\\\x=1

then,

g(0)=-\sqrt[3]{0-1}\\g(0)=-(-1)\\g(0)=1\\y=1

So,  we know that the function intercepts the axis at (1,0) and (0,1), meaning that the function match with the last given option

(g(x)=-\sqrt[3]{x-1})

Second,

Evaluating the function at (2,-1)

y=-\sqrt[3]{x-1}\\-1=-\sqrt[3]{2-1}\\-1=-\sqrt[3]{1}\\-1=-(1)\\-1=-1

-1=-1

It means that the function passes through the given point.

Hence,

The equation which represents g(x) is g(x)=-\sqrt[3]{x-1}

Have a nice day!

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<span>The opposite sides are parallel.
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