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3 years ago

Maria plans to rent a boat. The boat rental costs $60

Mathematics

2 answers:

uranmaximum [27]3 years ago

4 0

In this question, we're trying to find how many hours Maria can rent the boat for.

We know that the boat rental costs $60 per hour

We also know that she has to pay a one-time fee of $10 for a safety course

Turn this into a equation:

y = 60x + 10

However, she doesn't want to spent no more than $230. Add that to your equation

230 = 60x + 10

Solve the equation to see how many hours she can rent the boat for.

230 = 60x + 10

Subtract 10 from both sides

220 = 60x

Divide both sides by 60

3.67 = x

Since the boat can ONLY be rented by whole hours. With the money Maria has, she can only rent the boat for 3 hours.

Answer:

3 hours

irina1246 [14]3 years ago

3 0

Answer: she can rent a boat or 2 hrs and 30 mins

Step-by-step explanation:

60+10=70

70+60=130

130+60=190

190+30=220

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The ratio of ages of kissi and esinam is 3:5 and esinam is 3:5 The sum of ages of all 3 is 147 years.whats the age difference be

Sergio039 [100]

Answer:

48 years.

Step-by-step explanation:

Consider the complete question is "The ratio of ages of kissi and esinam is 3:5 and that of esinam and lariba is 3:5. The sum of ages of all 3 is 147 years. whats the age difference between oldest and youngest ?"

It is given that

Kissi : Esinam = 3:5 = 9:15

Esinam : Lariba = 3:5 = 15:25

So, the combined ratio is Kissi : Esinam : Lariba = 9:15:25

Let ages of Kissi, Esinam, Lariba are 9x, 15x and 25x.

Sum of ages of all 3 is 147 years.

$9x+15x+25x=147$

$49x=147$

$x=3$

The value of x is 3. So, the age of all three are

$Kissi=9x=9(3)=27$

$Esinam=15x=15(3)=45$

$Lariba=25x=25(3)=75$

Since Lariba is oldest and Kissi is youngest, therefore, the difference between their ages is

$75-27=48$

Hence, difference between oldest and youngest is 48 years.

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2 years ago

Write 99.124 in expanded form

Fofino [41]

The answer that you are looking for is
90+9+0.1+0.02+0.004

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The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual

Lerok [7]

$\Huge\bf{\underline{\red \dag { Aиѕωєя }}} \red \dag$

4 Packs of water and 7 Packs of candy bars.

So, we wanna know the smallest number that both 35 and 20 will go into.

Find the Least Common Multiple (LCM), but to find the LCM we need to find the prime factorization of each of the following number :-

$\sf {35 = 5(7)}$

$\sf \red {20 = 5(4)}$

$\sf {4 = 2(2)}$

$\sf \red {20 = 5(2)(2)$

~Now multiply all the numbers by 5 :-

$\sf \pink{5(7)(2)(2) = 35(2)(2) = 70(2) = 140}$

This means she needs 140 bottles of water and 140 candybars.

Water is sold in packs of 35, this means that she needs :

$\sf \orange{ \frac{140}{35} = 4\: packs \: of \: water}$

Candy bars are sold in packs of 20, this means she needs :

$\sf \green{ \frac{140}{20} = 7 \: packs \: of \: candy \: bars}$

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