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Anna71 [15]
3 years ago
15

How many solutions does the system have? {y=−2x+2y=x2−3x Enter your answer in the box.

Mathematics
1 answer:
navik [9.2K]3 years ago
3 0
ANSWER

The system has two solutions.

EXPLANATION

The given equations are

y=-2x + 2

and

y={x}^{2} - 3x

We equate both equations to obtain;

{x}^{2} - 3x =-2x + 2

This implies that,

{x}^{2} - 3x +2x - 2 = 0

{x}^{2} - x - 2 = 0

where a=1, b=-1,c=-2.

We find the discriminant, D=b²-4ac of this equation to be;

D = {(-1)}^{2} - 4(1)( - 2) = 9

Since the discriminant is greater than zero, it means the two functions intersected at two distinct points.


Hence the system has two solutions.
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The expression is a perfect square trinomial if and only if c = 121.

<h3>How to get the value of c?</h3>

A perfect square trinomial is written as:

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In this case, we have:

t^2 - 22t + c

We can rewrite this as:

t^2 - 2*11*t + c

Then we have:

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And we will have that:

c = b^2 = (-11)^2 = 121

Then we have:

t^2 - 2*11*t + 121

Which is a perfect square trinomial:

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If (a-bi)^2 = 13 - 12i, what is the product of a and b?
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Answer:

\large \boxed{\sf \ \ \ a\cdot b= 6 \ \ \ }

Step-by-step explanation:

Hello,

(a-bi)^2 = 13 - 12i\\\\ a^2+(bi)^2-2abi = 13-12i\\\\a^2-b^2-2abi=13-12i

Imaginary term must be the same so

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Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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