ANSWER:
The answer will be OT
Answer:
A 1
B 3
c 4
d 3
Explanation:
we are chaimpon boy i topped my school by cheating so donot study chill and watch movies like of sunny leon and Sabita bhabi
Answer:
α=0.625rad/s^2
v=340m/s
w=10rad/s
θ=320rad
Explanation:
Constant angular acceleration = ∆w/∆t
angular acceleration = 20/32
α=0.625rad/s^2
Linear velocity v=wr
v = 20×17= 340m/s
Average angular velocity
w0+w1/2
w= 0+20/2
w= 20/2
w=10rad/s
What angle did it rotate with
θ=wt
θ= 10×32
=320rad
Answer:
X = 5.44 m
Explanation:
First we can calculate the normal force acting from the floor to the ladder.
W₁+W₂ = N
W1 is the weigh of the ladder
W2 is the weigh of the person
So we have:
The friction force is:
Now let's define the conservation of torque about the foot of the ladder:
Solving this equation for X, we have:
Finally, X = 5.44 m
Hope it helps!
Answer:
it will show a continuous rise in value. The rise will be sinusoidal.
Explanation: