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ICE Princess25 [194]
3 years ago
15

a. Define Valency. b. Write the symbol and valency of the following : (i) Oxygen (ii) potassium 7. a. Magnesium burns in Oxygen

to form Magnesium Oxide. a) Name the reactants b) Name the Products c) Write the word equation for the above reaction.
Physics
2 answers:
sweet-ann [11.9K]3 years ago
6 0

Answer:

Oxygen-Symbol-O Potassium Symbol-K

34kurt3 years ago
6 0
<h3>⚘ <u>Your</u><u> </u><u>Answers</u><u>:</u></h3>

<u>A</u><u>)</u> Valency is the combining capacity of any element. Valence electrons refers to the electrons found in the outermost shell of the atom of the element.

<u>B</u><u>)</u> Symbol and valency:

  1. Oxygen(O) = (At. no. 8) = -2(Valency)
  2. Potassium(K) = (At. no. = 19) = +1(Valency)

<u>C</u><u>)</u> The reaction would be:

\large{ \boxed{ \rm{2Mg + O_2  \longrightarrow \: 2MgO}}}

  • <u>Reactants</u> = Magnesium and Oxygen
  • <u>Products</u> = Magnesium oxide
  • Word equation:

\large{ \boxed{ \rm{Magnesium + Oxygen  \longrightarrow Magnesium oxide.}}}

<u>━━━━━━━━━━━━━━━━━━━━</u>

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A 39-cm-long vertical spring has one end fixed on the floor. Placing a 2.2 kg physics textbook on the spring compresses it to a
Inessa05 [86]

Answer:

The spring constant is 215.6 N/m.

Explanation:

Given that,

Distance = 39 cm

Compresses length = 29 cm

Mass = 2.2 kg

We need to calculate the distance

Using formula of distance

x=l-l'

Put the value into the formula

x=39-29=10\ cm

We need to calculate the spring constant

Using formula of restoring force

F=kx

k=\dfrac{mg}{x}

Where, F = force

x = distance

Put the value into the formula

k=\dfrac{2.2\times9.8}{10\times10^{-2}}

k=215.6\ N/m

Hence, The spring constant is 215.6 N/m.

7 0
3 years ago
When Type NM cable is used with nonmetallic boxes not larger than 2 1/4 x 4 in., securing the cable to the box shall not be requ
Gekata [30.6K]

Answer:

8in

Explanation:

Multiply the race way side by 6

6 rather than 8.

6 0
3 years ago
Check my answer(there’s one above) I really just chose my best guess on this.for the ones below, can you provide a simple explan
almond37 [142]

#1

For closed pipe the fundamental frequency will be given as

f = \frac{v}{4L}

153 = \frac{340}{4L}

L = 0.56 m

L = 55 cm

#2

For open pipe the wavelength for Nth harmonic will be given as

n \times \frac{\lambda}{2} = L

\lambda = \frac{2L}{n}

#3

for a closed pipe the frequency is given as

f = \frac{nv}{4L}

here for third harmonic n = 3

f = \frac{3v}{4L}

now plug in all values

235 = \frac{3\times 340}{4L}

L = 1.09 m

L = 109 cm

#10

since in the given figure there are three complete loops

so in this case the <em>number of harmonics are THREE</em>

3 0
3 years ago
The sound from a loud speaker has an intensity level of 80 db at a distance of 2.0m. Consider the speaker to be a point source,
Tamiku [17]

Answer:

2.83m

Explanation:

The information that we have is

Intensity at 2.0 m: I=80dB and r_{1}=2m

we need an intensity level of: I_{2}=40dB

thus, we are looking for the distance r_{2}.

which we can find with the law for intensity and distance:

(\frac{r_{2}}{r_{1}} )^2=\frac{I_{1}}{I_{2}}

we solve for r_{2}:

\frac{r_{2}}{r_{1}}=\sqrt{\frac{I_{1}}{I_{2}} }\\\\r_{2}=r_{1}\sqrt{\frac{I_{1}}{I_{2}} }

and we substitute the known values:

r_{2}=(2m)\sqrt{\frac{80dB}{40dB} }\\\\r_{2}=(2m)\sqrt{2}\\ r_{2}=2.83m

at a distance of 2.83m the intensity level is 40dB

5 0
3 years ago
Coherent light from a sodium-vapor lamp is passed through a filter that blocks everything except for light of a single wavelengt
s2008m [1.1K]

Answer:

λ = 6.61 x 10⁻⁷ m = 661 nm

Explanation:

From the Young's Double Slit experiment, the the spacing between adjacent bright or dark fringes is given by the following formula:

Δx = λL/d

where,

Δx = fringe spacing = 2.86 mm = 2.86 x ⁻³ m

L = Distance between slits and screen = 2.12 m

d = slit separation = 0.49 mm = 0.49 x 10⁻³ m

λ = wavelength of light = ?

Therefore,

2.86 x 10⁻³ m = λ(2.12 m)/(0.49 x 10⁻³ m)

(2.86 x 10⁻³ m)(0.49 x 10⁻³ m)/(2.12 m) = λ

<u>λ = 6.61 x 10⁻⁷ m = 661 nm</u>

4 0
2 years ago
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