Sodium has an atomic mass of 23 and an atomic number of 11, so the

Physics

1 answer:

horrorfan [7]3 years ago

5 0

Answer:

12 Neutrons

Explanation:

So the mass of sodium is 22.990. You round it up to get 23(as stated in the problem). So, <em>what exactly is atomic mass?</em>

Atomic Mass is the total amount of neutrons and protons added up to form a total mass. So when you subtract 23-11 you get 12 Neutrons.

<u>Tip: </u>Don't know if you need this but-

The neutrons and protons are typically close in number (unless it's an isotope). So say that you subtract and the numbers of protons and neutrons aren't close at all. Well if that's the case, it's probably wrong.

hope this helps!!

You might be interested in

A worker pushes horizontally on a large crate with a force of 265.0 N and the crate moved 4.3 m. How much work was done?

trapecia [35]

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

work done = 265 × 4.3 = 1139.5

We have the final answer as

Hope this helps you

8 0

2 years ago

What is a mechanical wave?

Anika [276]

A wave that is oscillation of matter.. such as a water ripples

7 0

3 years ago

Read 2 more answers

Jefferson's administration was the beginning of popular government in the United States.

marshall27 [118]

He repealed federal taxes, Jefferson reduced military spending. He bought Louisiana from France. Considering only all these positive points and leaving aside the negative ones, one would say that the statement that "Jefferson's administration was the beginning of popular government in the United States." Is True!

8 0

3 years ago

A 5.0-μC charge is placed at the 0 cm mark of a meter stick and a -4.0 μC charge is placed at the 50 cm mark. At what point on a

Maksim231197 [3]

Answer:

The distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

Explanation:

Given that

q₁ = 5 μ C

q₂ = - 4 μ C

The distance between charges = 50 cm

d= 50 cm

Lets take at distance x from the charge μ C ,the electrical field is zero.

That is why the distance from the charge - 4 μ C = 50 - x cm

We know that ,electric field is given as

$E=K\dfrac{q}{r^2}$

$K\dfrac{5\ \mu}{x^2}=K\dfrac{4\mu }{(50-x)^2}\\\\\dfrac{5}{x^2}=\dfrac{4 }{(50-x)^2}\\\\\\5(50-x)^2=4x^2\\(50-x)^2=0.8x^2\\\\50-x =0.89x\\\ x=\dfrac{50}{1.89}\ cm\\\\\\x=26.45\ cm\\$