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Masteriza [31]
3 years ago
11

Sodium has an atomic mass of 23 and an atomic number of 11, so the

Physics
1 answer:
horrorfan [7]3 years ago
5 0

Answer:

12 Neutrons

Explanation:

So the mass of sodium is 22.990. You round it up to get 23(as stated in the problem). So, <em>what exactly is atomic mass?</em>

Atomic Mass is the total amount of neutrons and protons added up to form a total mass. So when you subtract 23-11 you get 12 Neutrons.

<u>Tip: </u>Don't know if you need this but-

The neutrons and protons are typically close in number (unless it's an isotope). So say that you subtract and the numbers of protons and neutrons aren't close at all. Well if that's the case, it's probably wrong.

hope this helps!!

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A DC generator is the same as a(n)

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A function that assigns a numerical value to each outcome of an experiment is called
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Random variable

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3 years ago
What is the energy released in this B- nuclear reaction 2K-&gt; 2Ca0,e? (The atomic mass of 42 K is 41.962403 u and that of 42Ca
Katyanochek1 [597]

<u>Answer:</u> The energy released in the given nuclear reaction is 3.526 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{19}^{42}\textrm{K}\rightarrow _{20}^{42}\textrm{Ca}+_{-1}^{0}\textrm{e}

We are given:

Mass of _{19}^{42}\textrm{K} = 41.962403 u

Mass of _{20}^{42}\textrm{Ca} = 41.958618 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(41.962403-41.958618)=0.003785u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.003785u)\times c^2

E=(0.003785u)\times (931.5MeV) (Conversion factor: 1u=931.5MeV/c^2 )

E=3.526MeV

Hence, the energy released in the given nuclear reaction is 3.526 MeV.

7 0
4 years ago
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