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Mamont248 [21]
3 years ago
5

Which of the following is a correct tangent ratio of the figure?

Mathematics
1 answer:
V125BC [204]3 years ago
5 0

Answer:

tan 72°=58/19

Step-by-step explanation:

i think this is the right answer

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Answer: 2

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PLEASE HELP ME
krok68 [10]
<h3>#29</h3>

<u>Find the value of x:</u>

  • 7x - 2 = 55 + 4x (as corresponding angles)
  • 7x - 4x = 55 + 3
  • 3x = 57
  • x = 19

<u>Find the value of y:</u>

  • y = 7x - 2 (as alternate exterior angles)
  • y = 7*19 - 2
  • y = 131
<h3>#30</h3>

<u>Find the value of x:</u>

  • 14x - 34 = 9x + 1 (as alternate interior angles)
  • 14x - 9x = 1 + 34
  • 5x = 35
  • x = 7

<u>Find the value of y:</u>

  • y + (9x + 1) = 90 (as complementary angles)
  • y = 90 - 9*7 - 1
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4 0
3 years ago
Write the equation of the line given the points (2,0) and (3.-1)
Juli2301 [7.4K]

Answer:

y = -1x + 2

Step-by-step explanation:

We need to find y = mx + b

Use the following equation

\frac{y_2-y_1}{x_2-x_1}

Plug in the values

\frac{-1-0}{3-2}  = \frac{-1}{1} = -1

We have found the slope(m) which is -1

We have to find y-int b

Plug in any given x,y into the slope formula

-1 = -1(3) + b

-1 = -3 + b

2 = b

At last the formula is

y = -1x + 2

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3 years ago
A survey was conducted among 78 patients admitted to a hospital cardiac unit during a​ two-week period. The data of the survey a
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Sets and set operations are ways of organizing, classifying and obtaining information about objects according to the characteristics they possess, as objects generally have several characteristics, the same object can belong to several sets, an example is the subjects of a school , where students (objects) are classified according to the subject they study (set).

The <em>intersection</em> of sets is a new set consisting of those objects that simultaneously possess the characteristics of each intersected set, the intersection of two subjects will be those students who have both subjects enrolled.

The <em>union</em> of sets is a new set consisting of all the objects belonging to the united sets, the union of two subjects will be all students of both courses.

In this case there are three sets B, C and S of which we are given the following information:

Answer

n(BꓵSꓵC)=5

n(BꓵS)=10 – 5 = 5

n(BꓵC)=12 – 5 = 7

n[(BꓵC)ꓴ(BꓵS)ꓴ(CꓵS)]=21  – 5 – 5 – 7 = 4

n(B)=36 – 5 – 5 – 7 = 19

n(S)=30 – 5 – 5 – 4 = 16

n(C)=34 – 5 – 7 – 4 = 18

7 0
3 years ago
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