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Lapatulllka [165]
2 years ago
10

Pls help me guys! Thanks =P

Mathematics
1 answer:
Tema [17]2 years ago
6 0
(4*7/2)+(15*7)+(7*6/2) = 140
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Need help!ASAP!<br> Prove the following identities:
Semmy [17]

Answer:what kind of math u doing

Step-by-step explanation:

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3 years ago
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What is the circumference of quadrilateral ABED in cm?
Natasha2012 [34]

the perimeter of quadrilateral ABED is 36.

<h3 /><h3>What is circumference?</h3>

A circumference is the total distance around a plane shape. Another name for circumference is called perimeter

To calculate the circumference of the quadrilateral, we use the formula below.

Formula:

  • Peri. of ABED = /AB/+/BE/+/ED/+/DA/............. Equation 1

From the Diagram,

Given:

  • /AB/ = /DC/ = 8 cm,
  • /BE/ = 2×/DA/ = 2×6 = 12 cm
  • /ED/ = √(6²+8²) = √(36+64) = √100 = 10 cm
  • /DA/ = 6 cm

Substitute these values into equation 1

  • Peri. of quadrilateral ABED = 8+12+10+6
  • Peri. of quadrilateral ABED  = 36 cm

Hence, the perimeter of quadrilateral ABED is 36.

Learn more about circumference here: brainly.com/question/20489969

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4 0
1 year ago
Give 1 pair of Vertical and 1 pair of Supplementary angles
mojhsa [17]

Solution:

Vertical angles are a pair of opposite angles formed by intersecting lines. re vertical angles. Vertical angles are always congruent.

These two angles (140° and 40°) are Supplementary Angles because they add up to 180°:

Notice that together they make a straight angle.

Hence,

From the image

The following pairs form vertical angles

\begin{gathered} \angle1=\angle3(vertical\text{ angles)} \\ \angle2=\angle4(vertical\text{ angles)} \\ \angle5=\angle7(vertical\text{ angles)} \\ \angle6=\angle6(vertical\text{ angles)} \end{gathered}

Hence,

One pair of the vertical angles is ∠1 and ∠3

Part B:

Two angles are said to be supplementary when they ad together to give 180°

Hence,

From the image,

The following pairs are supplementary angles

\begin{gathered} \angle5+\angle6=180^0(supplementary\text{ angles)} \\ \angle5+\angle8=180^0(supplementary\text{ angles)} \\ \angle7+\angle8=180^0(supplementary\text{ angles)} \\ \angle6+\angle7=180^0(supplementary\text{ angles)} \\ \angle1+\angle2=180^0(supplementary\text{ angles)} \\ \angle1+\angle4=180^0(supplementary\text{ angles)} \\ \angle2+\angle3=180^0(supplementary\text{ angles)} \\ \angle3+\angle4=180^0(supplementary\text{ angles)} \end{gathered}

Hence,

One pair of supplementary angles is ∠5 and ∠6

8 0
11 months ago
[-1 + (-4)] + (6/7 + 1/7)
Radda [10]

Answer:-4

Step-by-step explanation:

-1 +-4 is -5 and 6/7 + 1/7 =1 so -5 +1=-4

4 0
2 years ago
5
Dmitry [639]

Answer:

im pretty sure its ACD

Step-by-step explanation:

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