Let:
Vbu= Volume of the buret
Vbk= Volume of the beaker
A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:
x = Number of drips
a = volume of each drip
after how many drips will the volume of the solution in the buret and beaker be equal ? Vbu = Vbk:
B. 25 Km. The measure of BC is 25 km.
The easiest way to solve this problem is using the cosine theorem c = √a²+b²-2ab*cos A.
BC = √AC²+AB²-2(AC)(AB)*cos A
BC = √(21km)²+(14km)²-2(21km)(14km)*cos 89°
BC = √441km²+196km²-588km²*(0.017)
BC =√637km²-10.26km²
BC = √636.74km²
BC = 25.03km ≅ 25
X2-64=0
x2=64
x=8 because when multiplied by itself, and plugged back in, it works
Step-by-step explanation:
height= 4b
length = 2 + b
volume = 60in³
or, l ×b × h = 60in³
or, (2+b) × b × 4b = 60in³
or, 4b²(2+b) = 60in³
or, 8b² + 4b³ = 60
or, 2b² + b³ = 15
or, b³ + 2b² -15= 0
b= 1.95
l= 2+1.95=3.95
h= 4×1.95 = 7.8
