MRQS=360-mSR. or mRQS=31x+13...To solve the measure of the minor arc RQS you would use this... 31x+13+(6+18x/2. )=360.
This is the answer .
If you need more explanation I am free
The Area is the width<span> times the </span>height<span>: A = w x h;
Then, 64 = w x h;
h = 4 + w;
64 = 4w + w^2;
w^2 + 4w - 64 = 0;
We solve this equation: w1 </span>≈ 6,24 > 0 (okay); w2 ≈ - 10,24 < 0 (not okay);
<span>Finally, h1 </span>≈ 10,24;<span>
</span>
Answer:
m= 1/4
Step-by-step explanation:
tried helping I don't know if this is the right way to do it for you