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3 years ago

Plzz help I don't know how to solve this question so can you help me.

Mathematics

2 answers:

NARA [144]3 years ago

5 0

Answer:

f(-1) = 7^x

f(0) = 7^x

f(1) = 7^x

f(2) = 7^x

f(3) = 7^x

I think like this but not sure.

ddd [48]3 years ago

4 0

Plug in each of the x values to the x
Ex: 7^-1 or 7^0

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In your own words, explain the steps you would need to take to find slope from data in a table. Brainly work your magic.

mr_godi [17]

Answer:

In order to find the slope, you need to find the difference in the x values and the difference in the y values. To do this, you write out y2-y1/x2-x1, insert your x and y values, and get your answer. Then, you find your y-intercept (where the x value is 0).

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3 years ago

John ran 6 2/3 miles last week he ran 1 1/3 miles each day how many days did he run

Murljashka [212]

$6\frac{2}{3} = \frac{3(6) + 2}{3} = \frac{20}{3} miles$

$1\frac{1}{3} = \frac{3(1) + 1}{3} = \frac{4}{3} miles/day$

$\frac{20}{3} miles$ ÷ $\frac{4}{3} miles/day$

= $\frac{20(miles)}{3}$ * $\frac{3(days)}{4 (miles)}$

= $\frac{20(3) days}{3(4)} = \frac{20 days}{4} = 5 days$

Answer: 5 days

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3 years ago

A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.

olga55 [171]

We know that:

$(x-a)^2+(y-b)^2=r^2$

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}$

and all we have to do is solve it for a, b and r.

There will be:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\
$

From equations (II) and (III) we have:

$\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}$

and from (I) and (II):

$\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}$

Now we can easly calculate a and b:

$\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}$

Finally we calculate $r^2$ :

$a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}$

And the equation of the circle is:

$(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}$

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3 years ago

Estimate 49.419-27.276 by first rounding each number to the nearest thousand.

Wewaii [24]

Answer:

22.143

Step-by-step explanation:

49.419-27.276=22.143

6 0

3 years ago

The distance between the two points (4,1) and (9,1) is

Rzqust [24]

Answer:

5 units. Since they have the same y coordinate the x coordinate determines the distance from each other. In the case 9-4=5.

6 0

3 years ago

Plzz help I don't know how to solve this question so can you help me. ​

Plzz help I don't know how to solve this question so can you help me.