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Fynjy0 [20]
3 years ago
11

Kevin has a stamp collection he keeps 10 of the stamps in an album which is only 5% of his entire collection.what is the total n

umber of stamps in his collection
Mathematics
2 answers:
motikmotik3 years ago
4 0
200 total stamps in the collection
200 x 0.05= 10
Verizon [17]3 years ago
3 0

Answer:

Step-by-step explanation:

200

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A map has a scale of 3 centimeters = 26 kilometers. If two cities are 7 centimeters apart on the map, what is the actual distanc
maw [93]

Answer:

The answer to your question is 60.7 km

Step-by-step explanation:

This is a ratio and proportion problem, so let's write the proportion.

                                  3  :  26  : :  7  :  x

1.- Convert the expression to a fractional form.

                                  \frac{3}{26} = \frac{7}{x}

2.- Solve the proportion, cross multiplying and back off.

                                 x = \frac{26 x 7}{3}

                                 x = \frac{182}{3}

                                 x = 60.7 km

                         

5 0
3 years ago
A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to fin
drek231 [11]

Answer:

The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance

Step-by-step explanation:

The null hypothesis is:

H_{0} = 28

The alternate hypotesis is:

H_{1} < 28

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position.

This means that n = 50, X = 26

Assume the population standard deviation is 6.2 weeks.

This means that \sigma = 6.2

Does the data provide sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance

We have to find the pvalue of Z, looking at the z-table, when \mu = 28. It if is lower than 0.05, it provides evidence.

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{26 - 28}{\frac{6.2}{\sqrt{50}}}

z = -2.28

z = -2.28 has a pvalue of 0.0113 < 0.05.

The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance

5 0
3 years ago
Select the correct answer.<br> What are the solutions to this quadratic equation?
ipn [44]

Answer:

B. 4 - 2√10

Step-by-step explanation:

This is the value of x when you plug it into the equation.
Hope this helped!

8 0
2 years ago
What is pq^5 pq^2 Greatest Common Factor????????
algol [13]
Pq^5 and pq^2

the GCF would be : pq^2
7 0
3 years ago
PLZ I REALLY NEED HELP Find the values of x and y in parallelogram PQRS
brilliants [131]

Answer:

x = 5 and y = 7

Step-by-step explanation:

Given that,

PT = x+2, TR=y, QT=2x, TS=y+3

We need to find the value of x and y.

The diagonal of a parallelogram bisect each other. It means,

PT = TR and QT = TS

ATQ,

y = x+2 ...(1)

and

y+3 = 2x ....(2)

Subtracting equation (1) and (2).

y-(y+3) = x+2-2x

y-y-3 = 2-x

-3 = 2-x

x = 2+3

x = 5

Put the value of x in equation (1).

y = 5 + 2

y = 7

Hence, the values of x and y are x = 5 and y = 7.

4 0
3 years ago
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