ANSWER
Yes it is very true
<u>EXPLANATION</u>
If the two equations intersect at
then this point must satisfy the two equations.

We substitute
in to erquation (1)




We now substitute
in to erquation (2) also



Since the point satisfy all the two equations, it is true that they intersect at 
Answer:
(-3, 4)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -x + 1
2x + 3y = 6
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2x + 3(-x + 1) = 6
- Distribute 3: 2x - 3x + 3 = 6
- Combine like terms: -x + 3 = 6
- Isolate <em>x</em> terms: -x = 3
- Isolate <em>x</em>: x = -3
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: y = -x + 1
- Substitute in <em>x</em>: y = -(-3) + 1
- Simplify: y = 3 + 1
- Add: y = 4
Answer:
11
Step-by-step explanation:
33÷3= 11
11 shows every month
Answer: (5, -2)
Step-by-step explanation:

Substitute x-7 for y in 2nd equation

Solve for y

Answer:

Step-by-step explanation:

Formulas:
Area of a rectangle/square:


<u>Squares(2):</u>
5*5=25
Multiply by 2
<em>50 in.</em>
<u>Rectangles(4):</u>
5*3=15
Multiply by 4.
<em>60 in.</em>
<u>Total:</u>
Add.
50+60= 110 in2
I hope this helps!