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3 years ago

Which logarithmic graph can be used to approximate the value of y in the equation 4^y = 5?

Mathematics

1 answer:

qwelly [4]3 years ago

4 0

Answer:

Turn 4^y = 54

=5 into a logarithm and that is the graph

4^y = 54

=5 = log_4 x =ylog

x=y

log_4 x =ylog

x=y

y = log_4 xy=log

The graph of y = log_4 xy=log

x can be used.

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Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

3 years ago

Using substitution x+3y=3 3y-2x=12

frez [133]

Step-by-step explanation:

Given :-

x + 3y = 3
3y - 2x = 12

And we need to solve the equation using Substituting method . So on taking the first equation ,

$\rm\implies x + 3y = 3 \\\\\rm\implies x = 3 - 3y$

Put this value in (ii) :-

$\rm\implies 3y - 2x = 12 \\\\\rm\implies 3y - 2(3-3y)=12\\\\\rm\implies 3y -6-6y = 12 \\\\\rm\implies -3y = 18 \\\\\rm\implies y = -6$

Put this Value in (I) :-

$\\\\\rm\implies x = 3-3*-6 \\\\\rm\implies x = 3+18 \\\\\rm\implies x = 21$

Hence the Value of x is 21 and y is (-6) .

4 0

3 years ago

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Please solve the following quadratic equation and show your work: x^2 -x =30

saveliy_v [14]

Rewriting the equation as a quadratic equation equal to zero:
x^2 - x - 30 = 0
We need two numbers whose sum is -1 and whose product is -30. In this case, it would have to be 5 and -6. Therefore we can also write our equation in the factored form
(x + 5)(x - 6) = 0
Now we have a product of two expressions that is equal to zero, which means any x value that makes either (x + 5) or (x - 6) zero will make their product zero.
x + 5 = 0 => x = -5
x - 6 = 0 => x = 6
Therefore, our solutions are x = -5 and x = 6.

8 0

3 years ago

Find the solution to the following: *

Trava [24]

Answer:

First one: x = all real numbers

Second one: x = 0

Step-by-step explanation:

for the first one

given 8x+10=2(4x+5) we need to isolate the variable (x) using inverse operations

step 1 distribute the 2 to what is in the parenthesis ( 4x and 5 )

2 * 4x = 8x

5 * 2 = 10

now we have 8x + 10 = 8x + 10

step 2 subtract 8x from each side

8x - 8x = 0

now we have 10 = 10

subtract 10 from each side

10 - 10 = 0

we're left with 0 = 0 meaning that all real numbers are solutions

For the second one

given 3x-8=2(x-4) once again we need to isolate the variable using inverse operations

step 1 distribute the 2 to what is in the parenthesis (x - 4)

2 *x = 2x

2 * -4 = -8

now we have 3x - 8 = 2x - 8

step 2 add 8 to each side

-8 + 8 = 0

now we have 2x = 3x

step 3 subtract 2x from each side

3x - 2x = x

2x - 2x = 0

we're left with x = 0

5 0

3 years ago

Which expressions are equivalent to the one below?check all that apply. 21^x/3^x

mafiozo [28]

C and E and F are all the correct answers

7 0

3 years ago

Read 2 more answers