Solve the quadratic equation 6x^2-13x-28=0 by factoring.
1 answer:
First step to factor the trinomial, multiply the constant -28 with the leading coefficient 6.
So, -28 * 6 = - 168.
Next step is to breakdown -168 into two multiples so that their addition will result the coefficient of w= - 13.
So, -168 = -21 * 8.
And addition of - 21 and 8 will give - 13.
So, next step is to replace -13x with -21x + 8. Therefore,
6x² - 21x + 8x - 28 =0
(6x² - 21x) + (8x - 28 )=0 Make the group of two terms.
3x (2x - 7) + 4 (2x - 7) = 0 Take out the common factor from each group.
(2x - 7)(3x + 4) = 0 Again take out the common factor (2x -7).
So, 2x - 7 =0, 3x + 4 = 0 Set both the factor equal to 0.
2x = 7 , 3x = -4
So,
Hope this helps you !
You might be interested in
Answer:
The angle will be "48.7°".
Step-by-step explanation:
In ΔTBO, the given values are:
TB = 6,000 feet
BO = 9,000 feet
Now,
To find the angle,
⇒
On putting the estimated values, we get
⇒
⇒
⇒
⇒
Given t = time and h = height
From the equation.
h is the axis od symmetry
(h, k) is the vertex.
In the equation, h is 1 and k is 16.
So the maximum value is 16 at t = 1.
The ball reaches maximum at 16 and it takes t = 1 to reach the maximum point.