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2 years ago

6

A football is projected at an angle of 30 from the ground with a n initial velocity of 10 m/s, take acceleration due to gravity

is g= 10m/s2 .what is the time of flight

2 answers:

Liono4ka [1.6K]2 years ago

7 0

Answer:

${ \bf \: time \: of \: flight : s = 0} \\ { \tt \: s \: is \: displacement} \\ \\ s = ut + \frac{1}{2} a {t}^{2} \\ 0 = u \sin( \theta) t - \frac{1}{2} g {t}^{2} \\ u \sin( \theta)t = \frac{1}{2} g {t}^{2} \\2 u \sin( \theta) = gt \\ { \boxed{ \tt{formular : time \: of \: flight = \frac{2u \sin( \theta) }{g} }}} \\ t = \frac{2 \times 10 \times \sin(30 \degree) }{10} \\ { \green{ \boxed{ \tt{ \bf{answer : { \tt{time \: of \: flight =1 \: second }}}}}}} \\ \\ { \tt{becker \: jnr}}$

rusak2 [61]2 years ago

6 0

Answer: i dont know

Explanation:

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A heavy piece of hanging sculpture is suspended by a 90 cm-long, 5.0 g steel wire. When the wind blows hard, the wire hums at it

kupik [55]

Answer: The mass of the sculpture is 11.8kg

Explanation:

Using the equation of fundamental frequency of a taut string.

f = (1/2L)*√(T/μ) .... (Eqn1)

Where

f= frequency in Hertz =80Hz

T = Tension in the string = Mg

M represent the mass of the substance (sculpture) =?

g= 9.8m/s^2

L= Length of the string=90cm=0.9m

μ= mass density = mass of string /Length of string

mass of string =5g=0.005kg

L=0.9m

μ=0.005/0.9 = 0.0056kg/m

Using (Eqn1)

80= 1/(2*0.9) √(T/0.0056)

144= √(T/0.0056)

Square both sides

20736= T/0.0056

T= 116.12N

Recall that T =Mg

116.12= M * 9.8

M=116.12/9.8

M= 11.8kg

Therefore the mass of the sculpture is 11.8kg

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2 years ago

Can we travel back in time?

KATRIN_1 [288]

Answer:

I do not believe so.

Explanation:

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2 years ago

Folding is usually the result of what type of stress

I am Lyosha [343]

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3 years ago

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Consider a river flowing toward a lake at an average velocity of 3 m/s. the river height is 90m above the lake. what is the tota

strojnjashka [21]

Kinetic energy per unit of mass is

$K=\frac{v^{2} }{2}$

Given, $v=3m/s^{2}$

Therefore,

$K=\frac{(3^{2} m/s^{2} )^2}{2}$

$K=4.5 J/kg$

Now potential energy per unit mass is

$p=g\times h$

Given, $h=90 m$

Therefore,

$p= 9.8m/s^2 \times 90$

$p=882.9 J/kg$

Thus, total mechanical energy of the river water per unit mass is

$T=K+p=(4.5+882.9)J/kg$

$T=887.9 J/kg$

OR

$T=0.887 kJ/kg$

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2 years ago

You are standing on a skateboard, initially at rest. A friend throws a very heavy ball towards you. You can either catch the bal

harina [27]

To solve this problem we will apply the concept related to the moment, which describes the change in speed in proportion to the body mass. The momentum can be described under the general equation

$p = mv$

Where,

m = mass

v = Velocity

The change in momentum is the difference between the final moment and the initial moment

$\Delta p = p_f - p_i$

Where,

$p_f =$ Final momentum

$p_i =$ Initial momentum

After catching the ball, the ball comes to rest position and speed of the ball is zero.

$p_f = 0$

The change in momentum on catching the ball is

$\Delta p = 0 - mv$

$\Delta p = -mv$

The momentum during the catching of the ball is

$p_i = mv$

Now during deflection of the ball, we know that there is an initial momentum and a negative final momentum because it moves with the same speed but in the opposite direction, that is

$p_f = -mv$

The momentum is negative since during deflection the ball moves with same speed in opposite direction

$\Delta p = -mv-mv$

$\Delta p = 2-mv$

Therefore, the correct ansswer is B: catch the ball in order to minimize your speed on the skateboard

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3 years ago