Answer:
The total momentum before and after collision is 72000 kg-m/s.
Explanation:
Given that,
Mass of car = 1200 kg
Velocity of car = 10 m/s
Mass of truck = 2000 kg
Velocity of truck = 30 m/s
Using conservation of momentum
The total momentum before the collision is equal to the total momentum after collision.
![m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})V](https://tex.z-dn.net/?f=m_%7B1%7Dv_%7B1%7D%2Bm_%7B2%7Dv_%7B2%7D%3D%28m_%7B1%7D%2Bm_%7B2%7D%29V)
Where,
=mass of car
=velocity of car
=mass of truck
=velocity of truck
Put the value into the formula
![1200\times10+2000\times30=(1200+2000)V](https://tex.z-dn.net/?f=1200%5Ctimes10%2B2000%5Ctimes30%3D%281200%2B2000%29V)
![V=\dfrac{1200\times10+2000\times30}{(1200+2000)}](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1200%5Ctimes10%2B2000%5Ctimes30%7D%7B%281200%2B2000%29%7D)
![V = 22.5\ m/s](https://tex.z-dn.net/?f=V%20%3D%2022.5%5C%20m%2Fs)
Now, The total momentum before collision is
![P=m_{1}v_{1}+m_{2}v_{2}](https://tex.z-dn.net/?f=P%3Dm_%7B1%7Dv_%7B1%7D%2Bm_%7B2%7Dv_%7B2%7D)
![P=1200\times10+2000\times30](https://tex.z-dn.net/?f=P%3D1200%5Ctimes10%2B2000%5Ctimes30)
![P=72000\ kg-m/s](https://tex.z-dn.net/?f=P%3D72000%5C%20kg-m%2Fs)
The total momentum after collision is
![P=(m_{1}+m_{2})v_{2}](https://tex.z-dn.net/?f=P%3D%28m_%7B1%7D%2Bm_%7B2%7D%29v_%7B2%7D)
![P=(1200+2000)\times22.5](https://tex.z-dn.net/?f=P%3D%281200%2B2000%29%5Ctimes22.5)
![P= 72000 kg-m/s](https://tex.z-dn.net/?f=P%3D%2072000%20kg-m%2Fs)
Hence, The total momentum before and after collision is 72000 kg-m/s.
Answer:
2.5 cm
Explanation:
Number of spins in 12 seconds = 18
Number of spins in 1 second = 18 / 12 = 1.5
Number of spins in one second is called frequency.
f = 1.5 rps
ac = 2.2 m/s^2
Let r be the radius of coin
Centripetal acceleration, ac = r x w^2
2.2 = r x ( 2 x 3.14 x 1.5) ^2
2.2 = r x 88.7364
r = 0.025 m = 2.5 cm
Answer:
= 625 nm
Explanation:
We now that for
for maximum intensity(bright fringe) d sinθ=nλ n=0,1,2,....
d= distance between the slits, λ= wavelength of incident ray
for small θ, sinθ≈tanθ= y/D where y is the distance on screen and D is the distance b/w screen and slits.
Given
d=1.19 mm, y=4.97 cm, and, n=10, D=9.47 m
applying formula
λ= (d*y)/(D*n)
putting values we get
![\lambda = \frac{1.19\times10^{-3}\times4.97\times10^{-2}}{9.47\times10}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B1.19%5Ctimes10%5E%7B-3%7D%5Ctimes4.97%5Ctimes10%5E%7B-2%7D%7D%7B9.47%5Ctimes10%7D)
on solving we get
= 625 nm
Astronomer Hubble was the one that discovered that the universe has many galaxies and that the universe is expanding. That's why they name the Hubble Telescope under his name.
Well, st first we should find <span>initial momentum for the first person represented in the task which definitely must be :
</span>
![(65+0.045)*2.5](https://tex.z-dn.net/?f=%2865%2B0.045%29%2A2.5)
And then we find the final one :
![65*x + 0.045*30](https://tex.z-dn.net/?f=65%2Ax%20%2B%200.045%2A30)
Then equate them together :
So we can get the velocity, which is
![is 2.48 m/s](https://tex.z-dn.net/?f=%20is%202.48%20m%2Fs)
In that way, according to the main rules of <span>conservation of momentum you can easily find the solution for the second person.
Regards!</span>