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s344n2d4d5 [400]
3 years ago
7

ryan hypothesizes that darker colors heat up faster. he places a thermometer inside a red wool sock, a green cotton glove, and a

black nylon hat. whats wrong with his procedure?.
Physics
1 answer:
telo118 [61]3 years ago
3 0
Light are transfer through waves in the atmosphere and yes it  true that the darker the color is the more heat it could absorb thus it is also explain that the lighter the color is the less heat or light its absorb its because the light is bounces back through other form of light and it lessens the amount of heat in a substance. In Ryan's procedure the possible wrong that he done is the present of a green cotton glove. Green color are one of the color that bounces light and could not support the hypothesis of Ryan and the possible temperature he could get is not the accurate one.
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A projectile is launched from ground level to the top of a cliff which is 195 m away and 155 m high. If the projectile lands on
muminat

Answer:

66.02m/s

Explanation:

the equation describing the distance covered in the horizontal direction is

x=ucos\alpha t-(1/2)gt^{2} but the acceleration in the horizontal path is zero, hence we have

x=ucos\alpha t

Since the horizontal distance covered is 155m at 7.6secs, we have ucos\alpha =\frac{155}{7.6} \\ucos\alpha =20.38.............equation 1

Also from the vertical path, the distance covered is expressed as

y=usin\alpha t-(1/2)gt^{2}

since the horizontal distance covered in 7.6secs is 195m, then we have

y=usin\alpha t-(1/2)gt^{2}\\y=7.6usin\alpha -4.9(7.6)^{2}\\478.02=7.6usin\alpha \\usin\alpha =62.9...........equation 2

Hence if we divide both equation 1 and 2 we arrive at

\frac{usin\alpha }{ucos\alpha } =\frac{62.9}{20.38} \\tan\alpha =3.08\\\alpha =tan^{-1}(3.08)\\\alpha =72.02^{0}\\

Hence if we substitute the angle into the equation 1 we have

ucos72.02=20.38\\u=66.02m/s

Hence the initial velocity is 66.02m/s

3 0
4 years ago
Chemical reactions at varying depths on other planets, such as Jupiter, result in what?(1point)
omeli [17]
I believe the answer would be "Different Colors," hope this helps :)
7 0
3 years ago
What three variable factors determine the force of gravity between any two objects
zalisa [80]
The force of gravity between two objects is:
F = G*m1*m2/r^2

So, it is dependent of the two masses and the distance between their centers of mass.

If, you are referring to the force of gravity due to the earth, then the two factors are the mass of the object and the distance from the center of mass of the object and center of mass of the earth.
5 0
3 years ago
Read 2 more answers
A jogger runs 6 km north ,5 km east then another 4km north her average speed 8 km how long will it take her to complete her run
LekaFEV [45]

The time taken to complete her run is 1.9 hr.

<u>Explanation:</u>

Speed is a scalar quantity and it is defined as the ratio of distance covered to the time taken to cover that distance. As distance is also a scalar quantity, so the directions given in the problem can be ignored. Thus, the distance covered by the jogger is the sum of kilometers given in problem.

Distance covered = 6+5+4 = 15 km

And the speed is given as 8 km/hr.

So the time taken will be ratio of distance to speed.

\text { time }=\frac{\text {distance}}{\text {speed}}=\frac{15}{8}=1.9 \text { hour }

So the jogger will take 1.9 hr to complete her run.

8 0
4 years ago
Before a collision, a 50.0-kg object is moving at +5.0 m/s. Find the impulse that acted on the object if, after the collision, i
Virty [35]

Answer:

<em>J=600 kg m/s </em>

Explanation:

<u>Impulse And Momentum </u>

Suppose a particle is moving at a certain speed v_1 and changes it to v_2. The impulse J is equivalent to the change of linear momentum. The momentum can be computed by

p=mv

The initial and final momentums are given, respectively, by:

p_1=mv_1,\ p_2=mv_2

Thus, the change of momentum is

\Delta p=p_2-p_1=m(v_2-v_1)

It's equal to the Impulse J

J=\Delta p

J=m(v_2-v_1)

Our data is

m=50\ kg,\ v_1=5\ m/s,\ v_2=17\ m/s

J=50\ (17-5)

J=600\ kg\ m/s

7 0
3 years ago
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