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ratelena [41]
3 years ago
9

David is performing the following construction. Based on the markings that are present, what construction is he performing?

Mathematics
2 answers:
lora16 [44]3 years ago
8 0

Answer:

He is bisecting the angle BAC.

Step-by-step explanation:

First he puts the compass point at point A and draws 2 small arcs at D and E.  Then he places the compass point at D and then at E to form the 2 arcs that cross between the  2 line segments AB and AC.

The bisector is the line he can draw between A and the crossed arcs.

scZoUnD [109]3 years ago
3 0

Answer:

Bisecting an angle

Step-by-step explanation:

David first draw an angle CAB i.e \angle CAB

Then draw an arc cutting AC at D and AB at E .

With E as centre , draw an arc then with D as centre draw an arc

Both the arcs will intersect at some point .

If we join point A to this intersecting point , we get an angle bisector of \angle CAB

So, based on the markings that are present , he is actually bisecting the angle.

An angle bisector is a line or line segment which bisects an angle into two equal parts .

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I thought of a number, I added 1 3 4 to it, then I multiplied the result by 2 2 11 and I got 8. What was my number?
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Given:

In a number, adding 1\dfrac{3}{4}, then multiplying the result by 2\dfrac{2}{11} we get 8.

To find:

The unknown number.

Solution:

Let the unknown number be x.

According to the question,

(x+1\dfrac{3}{4})\times 2\dfrac{2}{11}=8

(x+\dfrac{1\times 4+3}{4})\times \dfrac{2\times 11+2}{11}=8

(x+\dfrac{4+3}{4})\times \dfrac{22+2}{11}=8

(x+\dfrac{7}{4})\times \dfrac{24}{11}=8

Multiply both sides by \dfrac{11}{24}.

x+\dfrac{7}{4}=8\times \dfrac{11}{24}

x+\dfrac{7}{4}=\dfrac{11}{3}

Subtract \dfrac{7}{4} from both sides.

x=\dfrac{11}{3}-\dfrac{7}{4}

x=\dfrac{44-21}{12}

x=\dfrac{23}{12}

x=1\dfrac{11}{12}

Therefore, the required number is 1\dfrac{11}{12}.

3 0
3 years ago
Maria makes money by commission rates. She gets 15% of everything she sells. If Maria sold $23000 worth of items this month, wha
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(x^{2} + 4)(x^{2} - 4)

To solve this question you must FOIL (First, Outside, Inside, Last) like so

First:

(x^2 + 4)(x^2 - 4)

x^2 * x^2

x^4

Outside:

(x^2 + 4)(x^2 - 4)

x^2 * -4

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Inside:

(x^2 + 4)(x^2 - 4)

4 * x^2

4x^2

Last:

(x^2 + 4)(x^2 - 4)

4 * -4

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Now combine all the products of the FOIL together like so...

x^4 - 4x^2 +4x^2 - 16

Combine like terms:

x^4 - 4x^2 +4x^2 - 16

- 4x^2 +4x^2 = 0

x^4 - 16 <<<This is your answer

Hope this helped!

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Answer:

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