David is performing the following construction. Based on the markings that are present, what construction is he performing?
2 answers:
Answer:
Bisecting an angle
Step-by-step explanation:
David first draw an angle CAB i.e
Then draw an arc cutting AC at D and AB at E .
With E as centre , draw an arc then with D as centre draw an arc
Both the arcs will intersect at some point .
If we join point A to this intersecting point , we get an angle bisector of
So, based on the markings that are present , he is actually bisecting the angle.
An angle bisector is a line or line segment which bisects an angle into two equal parts .
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Answer:
15 seconds
Step-by-step explanation:
If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy: the dog's rate is 150 and the squirrel's is 100. The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know: the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up. Since we don't know what d is, we will just call it d! Now it seems as though we have 2 unknowns which is a problem. However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other. Here's the dog's equation:
d = rt
d+200 = 150t
And the squirrel's:
d = 100t
If we solve both for t and set them equal to each other we have:
Now we can cross multiply to solve for d:
150d = 100d + 20,000 and
50d = 20,000
d = 400
But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took. So sub that d value back into one of the equations we have solved for t and do the math:
That's 1/4 of a minute which is 15 seconds.