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Kipish [7]
2 years ago
11

The process of adding a known amount of solution of known concentration to determine the concentration of another solution is ca

lled?
Chemistry
2 answers:
uranmaximum [27]2 years ago
7 0

Answer:

It is the process in which a known amount of solution of known concentration is added to the concentration of the another solution to determine the concentration of unknown solution.

Explanation:

Phoenix [80]2 years ago
5 0

Answer:

Titration

Explanation:

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Three blocks are shown here pls HELPPPP:
White raven [17]

Answer: I am confident the answer is B

Explanation:

forgive me if im wrong

5 0
2 years ago
When many atoms are split in a chain reaction, a large explosion occurs. This is an example of what type of energy conversion? (
lara31 [8.8K]

Answer:

I think is chemical and nuclear

8 0
3 years ago
Read 2 more answers
What object has a mass of 10 grams and a volume of 2 mL
Elena-2011 [213]

Answer:

Destiny = 5 g/ml

Explanation:

The formula for density is d=

Knowing this, divide your mass by volume:

10 g / 2 ml = 5 g/ml

Final answer:

Destiny = 5 g/ml

3 0
2 years ago
The pressure of nitrogen gas at 35°C is changed from 0.89 atm to 4.3 atm. What will be its final temperature in Kelvin?
Alja [10]

Answer: The final temperature in Kelvin is 1488

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=0.89atm\\T_1=35^0C=(35+273)K=308K\\P_2=4.3atm\\T_2=?

Putting values in above equation, we get:

\frac{0.89}{308}=\frac{4.3}{T_2}\\\\T_2=1488K

Hence, the final temperature in Kelvin is 1488

8 0
3 years ago
14. Calculate the mass in grams of oxygen required to react completly with 0.75 moles of Aluminum.
cluponka [151]
  • 3mols of O_2 react with 4mol of Al
  • 3/4=0.75mol O_2 react with 1mol of Al

Moles of O_2:-

  • 0.75(0.75)
  • 0.5625mol

Mass of O_2:-

  • moles(Molar mass)
  • 0.5625(32)
  • 18g

Option B

8 0
2 years ago
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