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3 years ago

A weather balloon at Earth’s surface has a

Chemistry

1 answer:

tigry1 [53]3 years ago

6 0

The temperature : 263.016 K

<h3>Further explanation</h3>

Combined with Boyle's law and Gay Lussac's law

$\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}$

P1 = initial gas pressure (N/m² or Pa)

V1 = initial gas volume (m³)

P2 = gas end pressure

V2 = the final volume of gas

T1 = initial gas temperature (K)

T2 = gas end temperature

P1=760 mmHg

V1= 4 L

T1 = 275 K

P2=704 mmHg

V1=4.13 L

$\tt \dfrac{760\times 4}{275}=\dfrac{704\times 4.13}{T_2}\\\\T_2=263.016~K$

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<h3>The answer is 3.44 g/cm³</h3>

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