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GREYUIT [131]
2 years ago
9

Convert 530 grams of Sodium carbonate (Na2CO3) into moles of Sodium carbonate (Na2CO3)

Chemistry
1 answer:
Vesna [10]2 years ago
6 0

1. 5 moles

2. 75.6 grams

3. 2 moles

4.  1.806 x 10²⁴ particles

<h3>Further explanation</h3>

Given

mass and moles of compound

Required

mass, moles and number of particles

Solution

1. 530 g Na2CO3

mol = 530 g : 106 g/mol

mol = 5

2. 4.2 moles H2O

mass = 4.2 moles x 18 g/mol

mass = 75.6 grams

3. 12.04 x 10²³ O2

mol =   12.04 x 10²³ : 6.02  x 10²³

mol = 2

4. 3 moles of Mg

particles = 3 x 6.02  x 10²³

particles = 1.806 x 10²⁴

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In the following reaction, what is the quantity of heat (in kJ) released when 5.87 moles of CH₄ are burned?
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Taking into account the definition of enthalpy of a chemical reaction, the quantity of heat released when 5.87 moles of CH₄ are burned is 4,707.74 kJ.

The enthalpy of a chemical reaction as the heat absorbed or released in a chemical reaction when it occurs at constant pressure. That is, the heat of reaction is the energy that is released or absorbed when chemicals are transformed into a chemical reaction.

The enthalpy is an extensive property, that is, it depends on the amount of matter present.

In this case, the balanced reaction is:

CH₄ (g) + 2 O₂ (g) → CO₂ (g) + 2 H₂O(g)

and the enthalpy reaction ∆H° has a value of -802 kJ/mol.

This equation indicates that when 1 mole of CH₄ reacts with 2 moles of O2, 802 kJ of heat is released.

When 5.87 moles of CH₄ are burned, then you can apply the following rule of three: if 1 mole of CH₄ releases 802 kJ of heat, 5.87 moles of CH₄ releases how much heat?

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Finally, the quantity of heat released when 5.87 moles of CH₄ are burned is 4,707.74 kJ.

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