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Crazy boy [7]
3 years ago
10

A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°c. what is the magnitude of k at 75.0°c if ea =

85.6 kj/mol?
Chemistry
1 answer:
IgorC [24]3 years ago
8 0
According to this formula:
K= A*(e^(-Ea/RT) when we have K =1.35X10^2 & T= 25+273= 298K &R=0.0821
Ea= 85.6 KJ/mol So by subsitution we can get A:
1.35x10^2 = A*(e^(-85.6/0.0821*298))
1.35x10^2 = A * 0.03
A= 4333
by substitution with the new value of T(75+273) = 348K & A to get the new K
∴K= 4333*(e^(-85.6/0.0821*348)
  = 2.16 x10^2
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250 ml glass of lemon juice contains 20 grams of sugar. How much sugar is in 500 ml bottle
iren2701 [21]

There is 40 g of sugar in a 500 ml bottle of lemon juice

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

the concentration of sugar in lemon juice :

\tt \dfrac{20~g}{250~ml}=0.08~g/ml

So for 500 ml juice :

\tt 500\times 0.08=40~g~sugar

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The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a b
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Answer:

The answer is "\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}"

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When HCI is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:

CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\

 In this, the CH_3COOH is a weak acid so, it not completely dissociated.

CH_3COONa \ (aq) \ \ and \ NaCl were strong electrolytes they are completely dissociated.

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2032533 \sq22222rt[2]{?}

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A chemistry student weighs out of hypochlorous acid into a volumetric flask and dilutes to the mark with distilled water. He pla
riadik2000 [5.3K]

Answer:

<u><em>Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.</em></u>

A chemistry student weighs out 0.0941 g of hypochlorous acid (HClo) into a 250. ml. volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.2000 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits mL.

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