The balanced reaction is
3Na3PO4 + 2CuSO4 ------> 3Na2SO4 + Cu3(PO4)2
To balance this reaction of double displacement, we see first that this reaction maintain the valence numbers of every atom.
Then, to have the same value of Na in the two sides of the reaction we multiply for the number of the other side. So,
(Na3PO4)x 2
(Na2SO4)x3
As we can see either, we need to balance PO4 cause there are two molecules of this in the reactant side, so we have two molecules of PO4 in the product either.
Then we get
3Na3PO4 + 2CuSO4 ------> 3Na2SO4 + Cu3(PO4)2
To probe that balance was correct, you can verify that the charges are exactly the opposite.
Good morning
Chemical reactions can be detected by changes in : Temperature and color
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In order to find the answer, use an ICE chart:
Ca(IO3)2...Ca2+......IO3-
<span>some.......0..........0 </span>
<span>less.......+x......+2x </span>
<span>less........x.........2x
</span>
<span>Ca(IO₃)₂ ⇄ Ca⁺² + 2 IO⁻³
</span>
K sp = [Ca⁺²][IO₃⁻]²
K sp = (x) (2 x)² = 4 x³
7.1 x 10⁻⁷ = 4 x³
<span>x = molar solubility = 5.6 x 10</span>⁻³ M
The answer is 5.6 x 10 ^ 3 M. (molar solubility)
Answer:
The answer to your question is below
Explanation:
To solve this problem use the general formulas for Alkanes, Alkenes, and Alkynes.
Alkanes Cn H(2n + 2)
Alkenes Cn H (2n) "n" is the number of Carbons
Alkynes Cn H (2n - 2)
a) CH₄ C₁ H 2(1) +2 = C₁H₂ + ₂ = CH₄ Alkane
b) C₂H₄ C₂ H₂(₂) Alkene
c) C₃H₆ C(₃) H₂ (₃) Alkene
d) C₂H₂ C₂ H₂(₂) - 2 = C₂H₄ - ₂ = C₂H₂ Alkyne
e) C₁₀H₂₂ C₁₀ H₂(₁₁) Alkene
Answer:
d) a pure substance that can be separated into different elements by chemical means.
Explanation:
Hello,
Sodium chloride (NaCl) is a chemical compound composed by sodium and chlorine. They are chemically bonded through a ionic bond which means that the sodium transfers just one electron (valence electron) to the chlorine to form the bond. Now, if we want to separate them, we must induce a chemical process because bond breaking implies a chemical change, not physical. Thus, a typical way to separate them (break the bond) is via electrolysis in which an electric driving force induce the aforementioned breakdown.
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