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zlopas [31]
3 years ago
15

Identify the Following as either Alkanes, alkynes or alkenes

Chemistry
2 answers:
puteri [66]3 years ago
5 0

Answer:

The answer to your question is below

Explanation:

To solve this problem use the general formulas for Alkanes, Alkenes, and Alkynes.

Alkanes           Cn H(2n + 2)

Alkenes           Cn H (2n)              "n" is the number of Carbons

Alkynes            Cn H (2n - 2)

a) CH₄             C₁ H 2(1) +2   = C₁H₂ + ₂ = CH₄       Alkane

b) C₂H₄            C₂ H₂(₂)                                           Alkene

c) C₃H₆             C(₃) H₂ (₃)                                        Alkene

d) C₂H₂            C₂ H₂(₂) - 2  = C₂H₄ - ₂ = C₂H₂        Alkyne

e) C₁₀H₂₂          C₁₀ H₂(₁₁)                                          Alkene

Taya2010 [7]3 years ago
3 0

1) CH4: alkane

2) C2H4: alkene

3) C3H6: alkene

4) C2H2: alkyne

5) C10H22: alkane

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antiseptic1488 [7]

During endothermic phase change, the potential energy of the system always increases while the kinetic energy of the system remains constant. The potential energy of the reaction increases because energy is been added to the system from the external environment.

<u>Explanation</u>:

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3 years ago
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Calculate the pH of the following simple solutions:
IceJOKER [234]

Answer :

(1) pH = 1.27

(2) pH = 13.35

(3) The given solution is not a buffer.

Explanation :

<u>(1) 53.1 mM HCl</u>

Concentration of HCl = 53.1mM=53.1\times 10^{-3}M

As HCl is a strong acid. So, it dissociates completely to give hydrogen ion and chloride ion.

So, Concentration of hydrogen ion= 53.1\times 10^{-3}M

pH : It is defined as the negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

pH=-\log (53.1\times 10^{-3})

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<u>(2) 0.223 M KOH</u>

Concentration of KOH = 0.223 M

As KOH is a strong base. So, it dissociates completely to give hydroxide ion and potassium ion.

So, Concentration of hydroxide ion= 0.223 M

Now we have to calculate the pOH.

pOH=-\log [OH^-]

pOH=-\log (0.223)

pOH=0.65

Now we have to calculate the pH.

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-0.65=13.35

<u>(3) 53.1 mM HCl + 0.223 M KOH</u>

Buffer : It is defined as a solution that maintain the pH of the solution by adding the small amount of acid or a base.

It is not a buffer because HCl is a strong acid and KOH is a strong base. Both dissociates completely.

As we know that the pH of strong acid and strong base solution is always 7.

So, the given solution is not a buffer.

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