Answer:
Na3PO4 is excess reactant, CaCl2 is limiting reactant.
Explanation:
3CaCl2 + 2Na3PO4 ---> Ca3(PO4)2 + 6NaCl
from reaction : 3 mol 2 mol
given: 6 mol 5 mol (X)
X = (6*2)/3 = 4 mol Na3PO4
For 6 mol CaCl2 we need 4 mol Na3PO4, but we have 5 mol Na3PO4,
Na3PO4 is excess reactant, so CaCl2 is limiting reactant.
Answer:
The common ion will be di-positive ion.
Explanation:
The ionization energy is defined as the amount of energy needed for removal of most loosely bound electron from an isolated atom in gaseous state.
The low ionization energy shows that the atom is able to give electron easily as after losing electron it may attain noble gas configuration or half filled stability.
Here the first and second ionization energy, both are low suggesting that the element is ready to give two electrons easily to form a di-positive ion however the third ionization energy is high which shows that it will not form tri-positive ion commonly.
Answer:
11.3 g of 
are produced from 36.0 g of 
Explanation:
1. The balanced chemical equation is the following:
2. Use the molar mass of the , the molar mass of the and the stoichiometry of the balanced chemical reaction to find how many grams of are produced:
Molar mass = 18
Molar mass = 17
Therefore 11.3 g of are produced from 36.0 g of
I think it’s B not quite sure ! Sorry
