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4 years ago

-25 Points-

Mathematics

2 answers:

Anuta_ua [19.1K]4 years ago

7 0

Answer:

(x-2)^2+(y-1)^2=13

Center of the circle: (2,1)

Radius: sqrt(13)

(x-2)^2+(y-1)^2=13

Fittoniya [83]4 years ago

4 0

Answer:

(x-2)^2+(y-1)^2=13

Step-by-step explanation:

Center of the circle: (2,1)

Radius: sqrt(13)

(x-2)^2+(y-1)^2=13

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In a laboratory, scientist are performing chemical reactions.the amount of product formed by a reaction can be determined by equ

galina1969 [7]

Answer:

0.25

Step-by-step explanation:

The only constant in the equation is called the "constant of proportionality." Its value is 0.25.

The constant of proportionality is 0.25.

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In an equation of the form ...

y = kx

the constant k is called the <em>constant of proportionality</em>. It's a vocabulary (naming) question.

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4 years ago

After 6 months you have the same account balance as your friend and you have saved 280$. Write a linear equation that represents

astra-53 [7]

Answer:

y = 20x + 280

Step-by-step explanation:

The linear equation that represent your account balance is as follows:

Your friend

y = 25(6) + 250

= 400

And,

You

400 = m(6) + 280

6m = 400 - 280

6m = 120

m = 20

Now the equation of the account balance is

y = 20x + 280

Hence, the linear equation that represent your account balance is y = 20x + 280

4 0

3 years ago

A rope is 225 centimeters long.

mash [69]

Answer:

1.5 meters = 150 centimeters (multiply by 100)

Therefore, you should cut off $225-150=75$ centimeters.

5 0

2 years ago

The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x 2 + 5

Arada [10]

Answer:

Width = 15 inches Length = 20 inches

Step-by-step explanation:

The area of a rectangle is calculated using the following formula.

$A = Lx$ (1)

Where L is the length and x is the width of the rectangle

In this case we know that the length of the rectangle is 5 inches greater than its width. This means that:

$L = x + 5$ (2)

Also The area of a rectangle can be represented by the equation $x^2 + 5x = 300$

so to find the width x we solve the equation

$x^2 + 5x -300=0$ (3)

For an equation of the form $ax ^ 2 + bx + c = 0$ the quadratic formula is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case note that:

$a=1\\b=5\\c=-300$

Then:

$x=\frac{-5\±\sqrt{(5)^2-4(1)(-300)}}{2(1)}$

$x=\frac{-5\±\sqrt{25+1200}}{2}$

$x=\frac{-5\±\sqrt{1225}}{2}$

$x=\frac{-5\±35}{2}$

$x_1=\frac{-5+35}{2}$ → $x_1=15$

$x_2=\frac{-5-35}{2}$ → $x_2=-20$

We take the positive solution $x=15\ in$

Now we use equation (2) to find L

$L = x + 5$

$L = 15 + 5$

$L = 20\ in$

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