I think you are correct
y=ab^x
1=ab^3
4=ab^5
divide the second equation by the first one, you get b^2=4, so b=2
plug b=2 either equation you get b=1/8
Answer:
ABC = 30
Step-by-step explanation:
The two angles are complementary so they add to 90 degrees
2x+14 + x+7 = 90
Combine like terms
3x+21 = 90
Subtract 21 from each side
3x+21-21 = 90-21
3x = 69
Divide by 3
3x/3 = 69/3
x = 23
ABC = x+7 = 23+7 = 30
Answer:
Slope m = -(x+2)
The Slope of the secant m = 1
Step-by-step explanation:
From the given information:
The slope of the line passing through P(-2,-4) and Q ( x, f(X)) can be calculated as :
Slope m = ![\dfrac{f(x) - 4}{x+2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bf%28x%29%20-%204%7D%7Bx%2B2%7D)
Slope m = ![\dfrac{-4x-x^2-4}{x+2}](https://tex.z-dn.net/?f=%5Cdfrac%7B-4x-x%5E2-4%7D%7Bx%2B2%7D)
Slope m = ![\dfrac{-(x^2+4x+4)}{x+2}](https://tex.z-dn.net/?f=%5Cdfrac%7B-%28x%5E2%2B4x%2B4%29%7D%7Bx%2B2%7D)
Slope m = ![\dfrac{-(x+2)^2}{(x+2)}](https://tex.z-dn.net/?f=%5Cdfrac%7B-%28x%2B2%29%5E2%7D%7B%28x%2B2%29%7D)
Slope m = -(x+2)
Passing through P(-2,4) and Q(-3,3)
Slope of the secant m = -(x+2)
Slope of the secant m = -(-3 +2)
Slope of the secant m = -( -1)
The Slope of the secant m = 1