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Diano4ka-milaya [45]
2 years ago
10

A city water company charges homeowners based on how much water they use in thousands of gallons. The company progressively char

ges at a higher rate the more water that is used Based on the graph at the above how much does the city charged when a home owner uses the following number of gallons of water: ​

Mathematics
1 answer:
Dima020 [189]2 years ago
4 0

Answer:

  • 1700: $50
  • 2000: $60
  • 7000: $90

Step-by-step explanation:

You can read the answers from the graph. Find the usage on the horizontal scale, and look at the vertical scale to find the corresponding charge.

__

<h3>1700 gallons</h3>

The value 1700 is between 1000 and 2000, so will be between 1 and 2 on the horizontal scale. The graph is flat in that region. The charge is $50.

__

<h3>2000 gallons</h3>

The graph has a jump at 2 on the horizontal scale. The solid dot tells you that the charge is $60.

__

<h3>7000 gallons</h3>

At 7 on the horizontal scale, the graph is increasing from 80 to 100. At 7000 gallons, the line passes through the grid intersection indicating the charge is $90.

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Kyle works at a donut​ factory, where a​ 10-oz cup of coffee costs 95¢​, a​ 14-oz cup costs​ $1.15, and a​ 20-oz cup costs​ $1.5
Fynjy0 [20]

Answer:

Kyle filled 4 10-oz cups, 6 14-oz cups, and 4 20-oz cups.

Step-by-step explanation:

Let 10-oz, 14-oz, and 20-oz coffees be represented by the variables <em>a, b</em>, and <em>c</em>, respectively.

Since a total of 14 cups of coffee was served:

a+b+c=14

A total of 204 ounces of coffee was served. Therefore:

10a+14b+20c=204

A total of $16.70 was collected. Hence:

0.95a+1.15b+1.5c=16.7

This yields a triple system of equations. In order to solve a triple system, we should isolate the system to only two variables first.

From the first equation, let's subtract <em>a</em> and <em>b</em> from both sides:

c=14-a-b

Substitute this into both the second and third equations:

10a+14b+20(14-a-b)=204

And:

0.95a+1.15b+1.5(14-a-b)=16.7

In this way, we've successfully created a system of two equations, which can be more easily solved. Distribute:

For the Second Equation:

\displaystyle \begin{aligned} 10a+14b+280-20a-20b&=204\\ -10a-6b&=-76\\5a+3b&=38\end{aligned}

And for the Third:

\displaystyle \begin{aligned} 0.95a+1.15b+21-1.5a-1.5b&=16.7\\ -0.55a-0.35b&=-4.3\end{aligned}

We can solve this using substitution. From the second equation, isolate <em>a: </em>

<em />\displaystyle a=\frac{1}{5}(38-3b)=7.6-0.6b<em />

Substitute into the third:

-0.55(7.6-0.6b)-0.35b=-4.3

Distribute and simplify:

-4.18+0.33b-0.35b=-4.3

Therefore:

-0.02b=-0.12\Rightarrow b=6

Using the equation for <em>a: </em>

<em />a=7.6-0.6(6)=4<em />

<em />

And using the equation for <em>c: </em>

<em />c=14-(4)-(6)=14-10=4<em />

<em />

Therefore, Kyle filled 4 10-oz cups, 6 14-oz cups, and 4 20-oz cups.

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