Answer:
Step-by-step explanation:
![-4x^2+11x-6=-(4x^2-11x+6)=-(4x^2-8x-3x+6)\\\\=-\left[4x(x-2)-3(x-2)]=-(x-2)(4x-3)=(-4x+3)(x-2)](https://tex.z-dn.net/?f=-4x%5E2%2B11x-6%3D-%284x%5E2-11x%2B6%29%3D-%284x%5E2-8x-3x%2B6%29%5C%5C%5C%5C%3D-%5Cleft%5B4x%28x-2%29-3%28x-2%29%5D%3D-%28x-2%29%284x-3%29%3D%28-4x%2B3%29%28x-2%29)
Answer:
Hi ,
Cube of a number :
_______________
For a given number x we define cube
of x = x × x × x , denoted by x^3.
A given Natural number is a perfect
Cube if it can be expressed as the
product of triplets of equal factors.
Now ,
Write given number as product of
prime .
8788 = 2 × 4394
= 2 × 2 × 2197
= 2 × 2 × 13 × 169
= 2 × 2 × 13 × 13 × 13
= 2 × 2 × ( 13 × 13 × 13 )
Here we have only triplet of equal
factors i.e 13
To make 8788 into perfect Cube we
have multiply with 2.
Now ,
2 × 8788 = ( 2 × 2 × 2 ) × ( 13 × 13 × 13 )
17576 = ( 2 × 13 )^3 = ( 26 )^3 perfect
Cube
I hope this will useful to you.
The answer to your question is b
First and third, second can still be simplified.
X^2 - 7x + 12 = 0
x^2 - 4x - 3x + 12 = 0
x (x - 4) -3 ( x - 4) = 0
(x - 4) (x - 3) = 0
x = 3 , 4
Check the answer by plugging in 3 and 4 for x, if the equation equals zero then you have your answer.
