Answer:
Sample Response: To write a two-variable equation, I would first need to know how much Maya’s allowance was. Then, I would need the cost of playing the arcade game and of riding the Ferris wheel. I could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. My variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation I could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.
Answer:
13
Step-by-step explanation:
25d - 12 = ?
1 day = 25(1) - 12 = 13
12 + 13 = 25
Answer: 1,594,323
Step-by-step explanation:
No of leaves which falls daily on the first day = 1
No of days leaves falls = 14 days.
Solution:
No of leaves of day 1
= 1.
No of leaves on day 2
= 1*3
= 3
No of leaves of day 3
= 3*3
= 9
No of leaves of day 4
= 9*3
= 27
No of leaves on day 5
= 27*3
= 81
No of leaves on day 6.
= 81*3
= 243.
No of leaves of day 7
= 243*3
= 729
No of leaves on day 8
= 729 * 3
= 2187
No of leaves on day 9
= 2187 *3
= 6561
No of leaves on day 10
= 6561 * 3
= 19683
No of leaves on day 11
= 19683 * 3
= 59049
No of leaves on day 12
= 59049 *3
= 177147
No of leaves on day 13
= 531441
No of leaves on day 14
= 531441 * 3
= 1,594,323.
The number of leaves that would be on the ground on the 24th day of autumn would be 1,594,323
Answer:
small=15 large=40
Step-by-step explanation:
x=large box
y=small box
55 = x + y
50x + 55y = 2825
50x + 55( 55 - x) = 2825
50x + 3025 - 55x = 2825
0 = 55x - 50 x + 2825 - 3025
0 = 5x - 200
200 = 5x
x=40
y = 15
