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11111nata11111 [884]
3 years ago
15

Give the IUPAC name for each compound.

Chemistry
1 answer:
Kaylis [27]3 years ago
3 0

Answer:

a. 1-fluoro-3,3,4-trimethyl-pentane.

b. 1-iodo-3-ethyl-2-methyl-hexane.

c. 1,3-dichloro-5-dimethyl-hexane.

d. 1-bromo-3-methyl-cyclopentane.

Explanation:

Hello!

In this case, according to the IUPAC rules for the listed alkyl halides, we first need to name the halogens (considering periodic order) then alkyl radicals and finally the parent chain; thus, the names are given below:

a. 1-fluoro-3,3,4-trimethyl-pentane.

b. 1-iodo-3-ethyl-2-methyl-hexane.

c. 1,3-dichloro-5-dimethyl-hexane.

d. 1-bromo-3-methyl-cyclopentane.

e. 5-chloro-1-bromo-1,1,5-trimethyl-pentane (radicals are not clear).

Best regards!

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The percent yield of CO₂ is 93.3%.

<h3>What is the percent yield of CO₂?</h3>

The percent yield of a substance is given as follows:

  • Percent yield = actual yield/theoretical yield * 100 %

The equation of the reaction is used to determine the theoretical yield.

  • NaHCO₃ + CH₃COOH → CH₃COONa + H₂O + CO₂

Moe ratio of sodium bicarbonate and CO₂ is 1 : 1.

Given that sodium bicarbonate is the limiting reactant, the theoretical yield of CO₂ will be:

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Theoretical yield of CO₂ = 0.0239 moles * 22.4L/mol = 0.536 L

Actual yield = 0.50 L

Percent yield = 0.50/0.536 * 100%

Percent yield = 93.3%

In conclusion, the percent yield is the ratio of the actual yield and theoretical yield.

<em>Note that the complete question is given below:</em>

<em>Calculate your % yield of co2 in the reaction based on the grams of nahco3 being the limiting reagent in the reaction between 2.01 g of sodium bicarbonate and 24.6 mL of 1.5 M acetic acid? They produce 0.50 L of at s.t.p.</em>

<em />

Learn mores about percent yield at: brainly.com/question/8638404

#SPJ1

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