The structure of Dimethyl sulfide is H3C-S-CH3. It is produced naturally by some marine algae.
<u>Explanation:</u>
- DMS or dimethyl sulfide is formed by using two methyl groups combined with one sulfur atom. It is an organosulphur compound with a structural formula H3C-S-CH3.
- Most abundant biological sulfur compounds emitted to air and oceans by phytoplankton.
- DMS is produced naturally by the waste of dimethyl sulphoxide which is disposed into the sewer causing environmental odor problems.
- It is a flammable liquid that boils at 37 degrees celsius and a disagreeable smell produced from the cooking of certain vegetables also indicates bacterial contamination in the production of malt and brewing.
Number of O atoms : 24
<h3>Further explanation</h3>
Given
C₆H₁₂O₆ compound
Required
Number of atoms
Solution
A molecular formula shows the number of atomic elements in compound.
The empirical formula is the smallest comparison of the atoms
Glucose-C₆H₁₂O₆ is composed of 3 elements, namely C, H, and O.
The number of atoms in a compound can usually be seen from the subscript number after the atom and the reaction coefficient shows the number of molecules
So number of O atoms :
= 4 x 6 = 24 atoms
4 moles of sugar.
Explanation:
A mole is defined as the amount of a substance contained in Avogadro's number of particles 6.02 x 10²³.
1 mole of substance = 6.02 x 10²³. molecules
Given that;
the sample of sugar contains 1.505 x 10²³.molecules
The number of moles in this amount of sugar is 4 moles
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Number of moles brainly.com/question/13064292
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THE MOLECULE HAS A C=C AND AN -OH GROUP, SO IT IS CALLED AN ENE/OL, I.E., AN ENOL. ENOLS CAN BE FORMED ONLY FROM CARBONYL COMPOUNDS WHICH HAVE ALPHA HYDROGENS. THEY CAN BE FORMED BY ACID OR BASE CATALYSIS, AND ONCE FORMED ARE HIGHLY REACTIVE TOWARD ELECTROPHILES, LIKE BROMINE.
Answer:
CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)
Explanation:
According to this question, sodium carbonate reacts with sulfuric acid to form aqueous sodium sulfate, carbon dioxide and water. The balanced chemical equation is as follows:
Na2CO3(aq) + H2SO4(aq) → Na2SO4(aq) + CO2(g) + H2O(l)
- Next, split compounds that are aqueous into ions.
2Na+(aq) + CO32-(aq) + 2H+(aq) + SO42-(aq) → 2Na+(aq) + SO42-(aq) + CO2(g) + H2O(l)
- Next, we cancel out the spectator ions, which are ions that remain the same in the reactants and products side of a chemical reaction. The spectator ions in this equation are 2Na+(aq) and SO42-(aq).
CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)
- Hence, the balanced ionic equation is as follows:
CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)