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Nastasia [14]
3 years ago
9

30points, brainliest. Electrostatics Assignment very easy, need ASAP. 1-2

Physics
1 answer:
Lerok [7]3 years ago
4 0
1b) the atom could lose its valence electron

c) protons are equal to electrons so there is no need to include it

d) the atom would need to gain electrons to fill its valence shell to become negative
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I NEED HELP ASAP!!!!!
Ratling [72]

Answer:

D) momentum of cannon + momentum of projectile= 0

Explanation:

The law of conservation of momentum states that the total momentum of an isolated system is constant.

In this case, the system cannon+projectile can be considered as isolated, because no external forces act on it (in fact, the surface is frictionless, so there is no friction acting on the cannon). Therefore, the total momentum of the two objects (cannon+projectile) must be equal before and after the firing:

p_i = p_f

But the initial momentum is zero, because at the beginning both the cannon and the projectile are at rest:

p_i = 0

So the final momentum, which is sum of the momentum of the cannon and of the projectile, must also be zero:

p_f = p_{cannon}+p_{projectile} =0

6 0
4 years ago
How are different types of radiation arranged along the electromagnetic spectrum
Leona [35]
In order of increasing frequency: Radio, Microwaves, Infrared, Visible light, Ultra-violet, X-rays, Gamma rays. To remember this try:
Rabbits
Mates
In
Very
Unusual
e(X)pensive
Gardens
7 0
3 years ago
A Van de Graaff generator causes a total charge q to build up on a metal sphere of radius r. Which variable does not affect the
Maru [420]

Answer:

The radius r of the metal sphere.

Explanation:

From Gauss's law we know that for a spherical charge distribution with charge Q, the electrical field at distance R from the center of the sphere is given by

E=\frac{Q}{4\pi \epsilon_oR^2}

What is important to notice here is that the radius of the sphere does not matter because any test charge sitting at distance R feels the force as if all the charge Q were sitting at the center of the sphere.

This situation is analogous to the gravitational field. When calculating gravitational force due to a body like the sun or the earth, we take not of only the mass of the sun and the distance from it's center; the sun's radius does not matter because we assume all of its mass to be concentrated at the center.

6 0
3 years ago
A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 8.90 kg box that is sitting on the horizontal,
Lady_Fox [76]

Answer:

6.875 m/s

Explanation:

The force is variable which is given by

F(x) = 18 - 0.53 x

mass of the box, m = 8.9 kg

initially it is at rest at x = 0

Let the velocity is v after travelling a distance of 15 m.

According to the work energy theorem, the work done by all the forces is equal to the change in kinetic energy of the body.

Work done = change in kinetic energy

\int \overrightarrow{F}.d\overrightarrow{x}=\Delta  K.E

\int_{0}^{15} \left ( 18-0.53 x \right )dx=\frac{1}{2}\times m \left ( v^{2}-u^{2} \right )

\left ( 18x-0.265x^{2} \right )_{0}^{15}=\frac{1}{2}\times 8.9\times  \left ( v^{2}-0^{2} \right )

18 x 15 - 0.265 x 15 x 15 = 4.45 x v²

270 - 59.625 = 4.45 v²

v² = 47.275

v = 6.875 m/s

Thus, the final velocity of the box is 6.875 m/s.

4 0
3 years ago
Which scientist was the first to use the telescope in astronomy
Mashutka [201]

Answer:

Galileo Galilei

Explanation:

although Galileo was not the scientist who invented the telescope, he was the first to use it to observe celestial objects. he used the telescope in 1609. his discovery included more accurate information about the moon, the sun and some of the planets.

4 0
3 years ago
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