All categories

3 years ago

What are some errors made while doing measuring with a triple beam balance lab

Physics

2 answers:

nydimaria [60]3 years ago

7 0

Make sure the triple beam balance is at 0 before you begin.

Andru [333]3 years ago

4 0

Measurements are not correct , wrong measurements , Not at zero

You might be interested in

The maximum tension that a 0.80 m string can tolerate is 15 N. A 0.35-kg ball attached to this string is being whirled in a vert

zimovet [89]

Answer:

v=5.86 m/s

Explanation:

Given that,

Length of the string, l = 0.8 m

Maximum tension tolerated by the string, F = 15 N

Mass of the ball, m = 0.35 kg

We need to find the maximum speed the ball can have at the top of the circle. The ball is moving under the action of the centripetal force. The length of the string will be the radius of the circular path. The centripetal force is given by the relation as follows :

$F=\dfrac{mv^2}{r}$

v is the maximum speed

$v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{15\times 0.8}{0.35}} \\\\v=5.86\ m/s$

Hence, the maximum speed of the ball is 5.86 m/s.

3 0

3 years ago

Which statements describe velocity and acceleration? Check all that apply.

Tom [10]

Velocity is defined by rate of change in the position

which we can also write as

$v = \frac{ds}{dt}$

while acceleration is defined as rate of change in velocity

$a = \frac{dv}{dt}$

so acceleration and velocity both are rate of change in position and rate of change in velocity with respect to time respectively

out of all above statement the correct answer must be

<u>Acceleration equals change in velocity divided by time. </u>

4 0

3 years ago

Read 2 more answers

if you push your chair across the floor at a constant velocity how does the force of friction compare with the force you exert?

Alik [6]

-- If velocity is constant, then there is no net force
on the chair.

-- If there is no net force on the chair, then friction
must exactly balance out your push.

-- The force of friction is exactly equal in magnitude
to your push, and in exactly the opposite direction.

5 0

3 years ago

Read 2 more answers

For a projectile launched horizontally, which of the following best describes the downward component of a projectile's velocity?

Angelina_Jolie [31]

C. The downward component of the projectile's velocity continually increases

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform motion (with constant velocity) along the horizontal direction

- A uniformly accelerated motion, with constant acceleration (equal to the acceleration of gravity) in the downward direction

Here we want to study the downward component of the projectile's velocity. Since the vertical motion is a uniformly accelerated motion, the vertical velocity is given by:

$v=u+at$