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3 years ago

What are some errors made while doing measuring with a triple beam balance lab

Physics

2 answers:

nydimaria [60]3 years ago

7 0

Make sure the triple beam balance is at 0 before you begin.

Andru [333]3 years ago

4 0

Measurements are not correct , wrong measurements , Not at zero

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Light energy with very high amplitude would be perceived as ________.

s2008m [1.1K]

Answer:

High amplitude is equivalent to loud sounds.

Explanation:

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3 years ago

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A spherical balloon has a radius of 7.40 m and is filled with helium. Part A How large a cargo can it lift, assuming that the sk

malfutka [58]

Answer:

The mass of the cargo is $M = 188.43 \ kg$

Explanation:

From the question we are told that

The radius of the spherical balloon is $r = 7.40 \ m$

The mass of the balloon is $m = 990\ kg$

The volume of the spherical balloon is mathematically represented as

$V = \frac{4}{3} * \pi r^3$

substituting values

$V = \frac{4}{3} * 3.142 *(7.40)^3$

$V = 1697.6 \ m^3$

The total mass the balloon can lift is mathematically represented as

$m = V (\rho_h - \rho_a)$

where $\rho_h$ is the density of helium with a value of

$\rho_h = 0.179 \ kg /m^3$

and $\rho_a$ is the density of air with a value of

$\rho_ a = 1.29 \ kg / m^3$

substituting values

$m = 1697.6 ( 1.29 - 0.179)$

$m = 1886.0 \ kg$

Now the mass of the cargo is mathematically evaluated as

$M = 1886.0 - 1697.6$

$M = 188.43 \ kg$

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3 years ago

What is/are the products in the chemical equation?

Alla [95]

Answer:NH3

Explanation: product s are the result of the equation

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2 years ago

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What are the four forms that water takes when it returns to earth from the clouds?

Marina CMI [18]

Precipitation from the sky to the earth can come in several forms. Four types are: 1) Rain 2) Snow 3) Sleet (think of a more liquidity slushy snow) 4) Hail (pretty much solid chunks of ice)

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3 years ago

. A ball is thrown downward at a speed of 20 m/s. Choosing

a_sh-v [17]

The final velocity is $v = 20 - gt$

The distance traveled by the ball at time t is $y = y_o + (-20)t - \frac{1}{2} gt^2$

The maximum distance traveled by the object is $0 = (20)^2 - 2g(y-y_0)$

The given parameters;

initial velocity of the ball, u = 20 m/s

acceleration due to gravity, g = 9.8 m/s²

The final velocity can be calculate as;

$v = 20 - gt$

The distance traveled by the ball at time t;

$y = y_o + (-20)t - \frac{1}{2} gt^2$

The maximum distance traveled by the object is calculated as;

$v^2 = u^2 - 2g(y - y_0)\\\\0 = (20)^2 - 2g(y-y_0)$

Learn more here: brainly.com/question/16878713

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2 years ago