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Mumz [18]
3 years ago
12

A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coas

t in neutral so as to just reach the top of the 150 m high hill at B with vB = 0? Neglect friction.
Physics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 is 31.3 m/s

Explanation:

given information

car's mass, m = 1200 kg

h_{A} = 100 m

v_{A} = v_{A}

h_{B} = 150 m

v_{B} = 0

according to conservative energy

the distance from point A to B, h = 150 m - 100 m = 50 m

the initial speed v_{A}

final speed  v_{B} = 0

thus,

v_{B}² = v_{A}² - 2 g h

0 = v_{A}² - 2 g h

v_{A}² = 2 g h

v_{A} = √2 g h

    = √2 (9.8) (50)

    = 31.3 m/s

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Answer:

v = 87.46 m/s

Explanation:

The radial acceleration is the centripetal acceleration, whose formula is given as:

a_c = \frac{v^2}{r}

where,

a_c = centripetal acceleration = 17 m/s²

v = planes's speed = ?

r = radius of path = 450 m

Therefore,

17\ m/s^2 = \frac{v^2}{450\ m}\\\\v^2 = (17\ m/s^2)(450\ m)\\\\v = \sqrt{7650\ m^2/s^2}

<u>v = 87.46 m/s</u>

4 0
3 years ago
A capacitor is connected to an AC generator. As the generator's frequency is increased, what happens to the current in the capac
just olya [345]

Answer:

A) The current increases

Explanation:

In the DC limit (that means, very low frequency of the generator), the capacitor acts as an open circuit. In fact, a capacitor consists of two parallel plates which are separated from each other: this means that the current cannot flow through it, but it can only flow through the rest of the circuit.

In the case of a direct current (DC), therefore, the current in the circuit must be zero. For an AC current with very low frequency, the current is still very low, because the polarity of the generator changes direction not very often, so there is still enough time for the capacitor to "block" the current. However, when the frequency of the generator is increased, the polarity changes so fast that the current in the circuit can flow without having time of "hitting" the capacitor, so it has almost no effect and the current in the circuit is maximum.

3 0
3 years ago
A cart was pulled for a distance of 1 kilometer and the amount of work accomplished equaled 40,000 joules. With what force was t
goblinko [34]

Answer:

40 N

Explanation:

3 0
3 years ago
Archimedes' principle says that a 15 N object is buoyed up by a force that is
Afina-wow [57]

Answer:

<u />

  • <u> equal to the weight of the fluid that the body displaces</u>

Explanation:

<em />

<em>Archimides' principle </em>states the definition of buoyant force.

These are the imporant features of the buoyant force that you need to know:

  • Except for the very special vacuum condition, every body is immersed in a fluid.

  • The body is subject, at least, to two forces, its weight and the buoyant force.

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6 0
4 years ago
Read 2 more answers
In a softball game, a batter hits the ball at the velocity and angle shown
Kipish [7]
This problem is going to be pretty long to solve. So, prepare.

We’re interested in the change in our x position. So we have to break the velocity vector up into its components. Do cosine of 50 and then multiply by the magnitude of the velocity. I got 20.57m/s. That’s our initial velocity. And remember, horizontal acceleration is zero. The vertical acceleration, or any vertical component, has no effect on the horizontal components. In order to solve this problem, we want to utilize this equation:
Change in x-position = Vix*t

Let’s solve for time, which is dependent on the vertical components. The projectile will stop when it vertically hits the ground. Generally you want to use this equation for solving for time:
Yf = Yi + Viy*t + 1/2at^2
We didn’t solve for the vertical component yet, so let’s do that now. (Sine of 50)*(32) = 24.51m/s
Let’s now plug everything in:
0 = 0 + 24.5t - 4.9t^2
0 = 24.5t - 4.9t^2
0 = t(24.5 - 4.9t)
-24.5 = -4.9t
t = 5 seconds

The hard stuff is pretty much over. Put that 5 seconds into the other equation I said we wanted to use to solve the problem
Change in x-position (range) = (20.57)*(5)
= 102.85 meters

Answer B
5 0
4 years ago
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