Multiply the fraction by both things in the parenthesis.
Answer:
f(n) = -n^2 -3n +5
Step-by-step explanation:
Suppose the formula is ...
f(n) = an^2 +bn +c
Then we have ...
f(1) = 1 = a(1^2) +b(1) +c
f(2) = -5 = a(2^2) +b(2) +c
f(3) = -13 = a(3^2) +b(3) +c
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Here's a way to solve these equations.
Subtract the first equation from the second:
-6 = 3a +b . . . . . 4th equation
Subtract the second equation from the third:
-8 = 5a +b . . . . . 5th equation
Subtract the fourth equation from the fifth:
-2 = 2a
a = -1
Then substituting into the 4th equation to find b, we have ...
-6 = 3(-1) +b
-3 = b
and ...
1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation
5 = c
The formula is ...
f(n) = -n^2 -3n +5
Answer:
letter B is the answer (i think not sure )
Eight point six two is the answer
Answer:
Step-by-step explanation:
When you multiply, always start on the first value. In this case, this would be 2 from 72.
![==> 8[tex]and[tex]2 * 1](https://tex.z-dn.net/?f=%3D%3D%3E%208%5Btex%5D%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3Eand%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D2%20%2A%201)
Write now, you should have 82 as your first value.
Now for your second value, which would be 7. But first you need to add a zero, because you are doing the tens place.
<u>Now you put the two over your next equation:</u>
and
Now you should have 980 written.
<u>Now add your two numbers together:</u>
<u></u>
