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Tpy6a [65]
3 years ago
7

When finding​ percentiles, if the locator L is not a whole​ number, one procedure is to interpolate so that a locator of​ 23.75,

for​ example, leads to a value that is three fourths of the way between the 23rd and 24th scores. Use this method of interpolation to find for the set of test scores below. 51 54 64 68 72 74 76 83 94 94 99
Mathematics
1 answer:
inessss [21]3 years ago
7 0

Answer:

The answer is "94"

Step-by-step explanation:

Given data:

51,54,64,68,72,74,76,83,94,94,99

Find:

P_{75}=?P_{75}= (\frac{75(n+1)}{100})^{th} \ \ observation\\\\

      = (\frac{75(11+1)}{100})^{th} \ \ observation\\\\= (\frac{75(12)}{100})^{th} \ \ observation\\\\= (\frac{75 \times 12}{100})^{th} \ \ observation\\\\= (\frac{900}{100})^{th} \ \ observation\\\\= 9^{th} \ \ observation\\\\= 9^{th} \ number \ is = 94

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A: (1,3)

A': (1,-3)

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C: (-2,2)

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D: (-5,4)

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Find the missing number in the ratio table below.
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2 years ago
According to survey​ data, the distribution of arm spans for males is approximately Normal with a mean of 71.4 inches and a stan
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Answer:

a) 89.97% of men have arm spans between 66 and 76 ​inches.

b) The z-score for this​ person's arm span is 5.68. 0% of males have an arm span at least as long as this​ person

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 71.4 inches and a standard deviation of 3.1 inches.

This means that \mu = 71.4, \sigma = 3.1

a. What percentage of men have arm spans between 66 and 76 ​inches?

The proportion is the pvalue of Z when X = 76 subtracted by the pvalue of Z  when X = 66. The percentage is the proportion multiplied by 100.

X = 76

Z = \frac{X - \mu}{\sigma}

Z = \frac{76 - 71.4}{3.1}

Z = 1.48

Z = 1.48 has a pvalue of 0.9306

X = 66

Z = \frac{X - \mu}{\sigma}

Z = \frac{66 - 71.4}{3.1}

Z = -1.74

Z = -1.74 has a pvalue of 0.0409

0.9306 - 0.0409 = 0.8997

0.8997*100% = 89.97%

89.97% of men have arm spans between 66 and 76 ​inches.

b. A particular professional basketball player has an arm span of almost 89 inches. Find the​ z-score for this​ person's arm span. What percentage of males have an arm span at least as long as this​ person?

Z = \frac{X - \mu}{\sigma}

Z = \frac{89 - 71.4}{3.1}

Z = 5.68

The z-score for this​ person's arm span is 5.68.

Z = 5.68 has a pvalue of 1

1 - 1 = 0

0% of males have an arm span at least as long as this​ person

8 0
3 years ago
A newsletter publisher believes that 64d% of their readers own a Rolls Royce. A testing firm believes this is inaccurate and per
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Answer:

Step-by-step explanation:

The null hypothesis

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The alternative hypothesis

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This implies that the rejection of the null hypothesis shows that there is sufficient evidence to reject a newsletter publisher who believes that 64% of their readers own a Rolls Royce.

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3 years ago
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