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Aleks [24]
3 years ago
10

Which value represents the slope of the line that has an x-intercept at (-4,0) and a y-intercept at (0, -12) in the coordinate p

lane?
1.-3
2.-1/3
3.1/3
4.3
Mathematics
1 answer:
Lesechka [4]3 years ago
6 0
To find the gradient you do change in y/change in x so...

-12 - 0
————- = -12/4 = -3
0 - - 4

Hope this helps! Any questions let me know :)
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Verify the identity. <br> Please show your work.
m_a_m_a [10]

Step-by-step explanation:

To prove :

( 1 - sin x ) ( 1 + sin x ) = sec² x

LHS : -

( 1 - sin x ) ( 1 + sin x )

Formula / Identity : -

( a - b ) ( a + b ) = a² - b²

Here,

a = 1

b = sin x

( 1 - sin x ) ( 1 + sin x )

= 1 - sin² x

Identify : -

sin² θ + cos² θ = 1

cos² θ = 1 - sin² θ

Similarly,

1 - sin² x

= cos² x

= RHS

Hence verified.

5 0
3 years ago
Write the point-slope form of the equation of the horizontal line that passes through the point (2, 1). Include your work in you
asambeis [7]
2-1=1
y-y1=m(x-x1)
y-1=1(x-2)
5 0
3 years ago
Read 2 more answers
Find the value of x.<br> Round to the nearest tenth.
aev [14]

Answer:

  C ≈ 22.1°

Step-by-step explanation:

The law of cosines formula is given. Solving it for C, we find ...

  C = arccos((a^2 +b^2 -c^2)/(2ab))

where a and b are the sides adjacent to the angle.

Then we have ...

  C = arccos((14^2 +19^2 -8^2)/(2·14·19)) = arccos(493/532)

  C ≈ 22.1°

__

If you have a fair number of these to do, a spreadsheet is a useful tool. There are also triangle solver apps on the web or your local smart platform that will do this, too.

3 0
4 years ago
All vertical and horizontal cross-sections of any one cube are all the same size and shape. What about vertical and horizontal c
jek_recluse [69]
Yes they are all the same size and shape.
6 0
3 years ago
Select the correct answer.
svp [43]

Step-by-step explanation:

option B is correct as,

10 + x = -18

→ x = -18 -10

→ x = -28

<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care</u></em><em><u>!</u></em>

3 0
3 years ago
Read 2 more answers
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