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3 years ago

10

Which value represents the slope of the line that has an x-intercept at (-4,0) and a y-intercept at (0, -12) in the coordinate p

lane?
1.-3
2.-1/3
3.1/3
4.3

1 answer:

Lesechka [4]3 years ago

6 0

To find the gradient you do change in y/change in x so...

-12 - 0
————- = -12/4 = -3
0 - - 4

Hope this helps! Any questions let me know :)

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Simplify completely''''

34kurt

Answer:

$\displaystyle \frac{2(x + 3)}{5x - 2}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Terms/Coefficients
Factoring

Step-by-step explanation:

<u>Step 1: Define</u>

$\displaystyle \frac{2x^2 + 16x + 30}{5x^2 + 13x - 6}$

<u>Step 2: Simplify</u>

[Fraction] Factor numerator: $\displaystyle \frac{2(x + 3)(x + 5)}{5x^2 + 13x - 6}$
[Fraction] Factor denominator: $\displaystyle \frac{2(x + 3)(x + 5)}{(x + 3)(5x - 2)}$
[Fraction] Divide: $\displaystyle \frac{2(x + 3)}{5x - 2}$

8 0

2 years ago

Help help help help help

nekit [7.7K]

Answer:

C, C is the answer

5 0

3 years ago

How do I solve this?

Bad White [126]

Answer: <em>81</em>

Step-by-step explanation:

<em>3^4</em>

<em>3x3x3x3</em>

<em>3x3=9</em>

<em>9x3=27</em>

<em>27x3=</em><em>81</em>

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2 years ago

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How many feet in a rod?<br><br><br><br> 2.5<br><br> 4.5<br><br> 8.5<br><br> 16.5

Juli2301 [7.4K]

1 rod is equal to 16.5 feet

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3 years ago

Please help differentiate this!!!!!!!!!

vlada-n [284]

$\bf h=20ln(3t+2)+30\\\\
-------------------------------\\\\
\boxed{a}\\\\
\stackrel{0~years}{t=0}\qquad h=20ln[3(0)+2]+30\implies h=20ln(2)+30
\\\\\\
h\approx 43.86
\\\\\\
\boxed{b}\\\\
\stackrel{1~meter}{h=100}\qquad 100=20ln(3t+2)+30\implies 70=20ln(3t+2)
\\\\\\
\cfrac{70}{20}=ln(3t+2)\implies \stackrel{\textit{log cancellation rule}}{e^{\frac{7}{2}}=e^{ln(3t+2)}}\implies e^{\frac{7}{2}}=3t+2
\\\\\\
e^{\frac{7}{2}}-2=3t\implies \cfrac{e^{\frac{7}{2}}-2}{3}=t\implies 10.371817\approx t$

$\bf \boxed{c}\\\\
\cfrac{dh}{dt}=20\left(\cfrac{1}{3t+2}\cdot 3 \right)+0\implies \cfrac{dh}{dt}=20\left(\cfrac{3}{3t+2} \right)\\\\\\ \cfrac{dh}{dt}=\cfrac{60}{3t+2}
\\\\\\
\left. \cfrac{dh}{dt} \right|_{3}\implies \cfrac{60}{3(3)+2}\implies \cfrac{60}{11}
\\\\\\
\left. \cfrac{dh}{dt} \right|_{10}\implies \cfrac{60}{3(10)+2}\implies \cfrac{15}{8}$

5 0

3 years ago

Read 2 more answers